How they calculate the years?

Advanced Placement (AP)

1 answer:

Maru [420]2 years ago

5 0

Answer: A monk called Dionysius Exiguous calculated his own present year to be A.D. 525. Counting from that year reaches the current year. A.D. is now used to label the number of years in the Gregorian calendar, the most widely used calendar in the world and the unofficial global standard. You add one year every January 1.

Explanation:

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$x = 2 {y}^{2} - 4 \\ 2 {y}^{2} = x + 4 \\ \\ {y}^{2} = \frac{x + 4}{2} \\ \\ y = \frac{ + }{} \sqrt{ \frac{x + 4}{2} } \\ \\ y = \frac{ + }{} \frac{ \sqrt{x + 4} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \\ y = \frac{ + }{} \: \frac{ \sqrt{x + 4} \times \sqrt{2} }{ \sqrt{2} \sqrt{2} } \\ \\ y = \frac{ + }{} \frac{ \sqrt{2(x + 4)} }{2} \\ \\ y =\frac{ \sqrt{2(x + 4)} }{2} \\ \\ y = - \frac{ \sqrt{2(x + 4)} }{2}$

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with the root of both sides

$\sqrt{x} = \sqrt{ {(y - 5)}^{2} } \\ \\ \frac{ + }{} \sqrt{x} = y - 5 \\ \\ y = \sqrt{x} + 5 \\ y = - \sqrt{x} + 5$

I hope I helped you^_^

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