3 years ago

NEED HELP!

2 answers:

7 0

$f(x)=\cfrac{x^2+x-42}{x^2+3x-28}\implies \stackrel{f(x)}{0}=\cfrac{x^2+x-42}{x^2+3x-28}\implies 0 = x^2+x-42 \\\\\\ 0=(x+7)(x-6)\implies x= \begin{cases} 6\\ -7 \end{cases}$

marusya05 [52]3 years ago

7 0

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6.3630657
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1.38899554
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4.75206125

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