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3 years ago

What is the commom difference in the following arithmetic sequence??

1 answer:

5 0

Each increases by a certain amount called the common difference

4.4-2.8=1.6
6-4.4=1.6
7.7-6=1.7
hmm, some error
maybe you meant 7.6

common difference is 1.6

answer is C

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Help pls!!!!!!!!!!!!!!!!

Anastaziya [24]

ANSWER.

The correct answer is Option A

EXPLANATION.

The real number

$\sqrt{35}=5.916079783$

to 9 decimal places.

You can see that the decimals are not repeating, neither will they terminate.

Therefore the real number $\sqrt{35}$ is irrational because, the decimal does not terminate or repeat

Also note that,

$\sqrt{35}=\sqrt{5} \times \sqrt{7}$ .

That is,

$\sqrt{35}$ is a product of two irrational numbers, which still gives an irrational number.

8 0

3 years ago

Which expressions are equivalent to the given expression 6x-18y+36

umka21 [38]

Answer:

6(x-3y+6)

Step-by-step explanation:

6 0

2 years ago

Explain how 7/12 is greater than 1/3 but less than 2/3

cupoosta [38]

Think if you had 7/12 of a pie witch is 7 tiny piece opposed to 1 huge piece

3 0

3 years ago

A bag is filled with small and large marbles. The ratio of small to large marbles is 1:3. On your own sheet of paper, draw a tap

tiny-mole [99]

Tape diagrams are simple. Look at the picture I put in the comments

8 0

3 years ago

Read 2 more answers

Look at the following expression. Are there any values of x for which the expression is not defined under the set of real number

almond37 [142]

The expression $\frac{4}{\sqrt{x+2} }$ is not defined at x= -2 & for all values of x less than -2 .

<u>Step-by-step explanation:</u>

We have , a given expression as $\frac{4}{\sqrt{x+2} }$ : Basically we need to find domain for this function and see for which values of x the above function is undefined . Domain of a function is the set of values of x for which the function is defined . We have a rational expression, $\frac{4}{\sqrt{x+2} }$ it's a fractional function which means denominator can be 0 . Denominator = $\sqrt{x+2}$ $\neq 0$

⇒ $\sqrt{x+2}$ $\neq 0$

⇒ $x+2\neq 0$

⇒ $x \neq -2$

So , $x \neq -2$ . Also , Denominator is a square root expression so it can't be negative inside root ∴ $x+2 > 0$ ⇒ $x> -2$ i.e. x must be greater than -2.

Therefore, the expression $\frac{4}{\sqrt{x+2} }$ is not defined at x= -2 & for all values of x less than -2 .

4 0

3 years ago