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Burka [1]
2 years ago
5

6-10 divide, another onee thank you!!​

Mathematics
1 answer:
eduard2 years ago
5 0

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

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anzhelika [568]

Answer:

X = 5  

Step-by-step explanation:

I think there a problem with the question, If there is one less person in the group then the payment by each remaining person is must more than $2 than the previous, because the rent cost unchanged but the number of people in the group decreased.

Before, cost per person : \frac{40}{x}

After cost per person:  = \frac{40}{x -1 }

However, the payment by each remaining person is more than $2 than the previous, so

\frac{40}{x -1 }  =   \frac{40}{x}  + 2

<=> 2x^{2} - 2x -40 = 0

<=> X = 5  

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3 years ago
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Step-by-step explanation:

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3 years ago
Please help me with these 2 questions, please show work
muminat

Answer:

5x - 4 = 11

1/2x + 15 = 9

Step-by-step explanation:

I dont exactly know how u would show work.

If it says something is less than a number, then it will be at the back of the equation. So skip that part and u will see it says five times a number. The number is unknown therefore it will a variable (i chose x to be the variable). 5 times x is 5x. Minus the 4 would be 5x - 4. Then it says the equation equals 11. So 5x - 4 = 11.

If it says something is more than a number, it can be on either side of the equation using the commutative property of addition. But if we want to consider it being like subtraction, then it also will be in the back of the equation. A half is one over two (1/2). A half of x is 1/2x. Plus the 15 would be 1/2x + 15. It then states that the equation equals 9. So 1/2x + 15 = 9.

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