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Burka [1]
2 years ago
5

6-10 divide, another onee thank you!!​

Mathematics
1 answer:
eduard2 years ago
5 0

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

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Answer:

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Step-by-step explanation:

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5 0
3 years ago
Please solve for me!!
kifflom [539]

Answer:

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(
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+
x
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4
1
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(4+x) to
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x
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​
.
4
+
x
4
=
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3
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3
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​


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4
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4
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to
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1+
4
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.
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=
4
3
1+
4
x
​
=
3
4
​


3 Subtract
1
1 from both sides.
x
4
=
4
3
−
1
4
x
​
=
3
4
​
−1

4 Simplify
4
3
−
1
3
4
​
−1 to
1
3
3
1
​
.
x
4
=
1
3
4
x
​
=
3
1
​


5 Multiply both sides by
4
4.
x
=
1
3
×
4
x=
3
1
​
×4

6 Simplify
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3
×
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3
1
​
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4
3
3
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x
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4
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