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3 years ago

Order these numbers from least to greatest: -3.8, 3 3.-4, 0.

Mathematics

1 answer:

NeTakaya3 years ago

8 0

The answer would be,
0, -4, -3.8, 3.3

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A group of hikers walked 2 1/4 km in 3/4 hour.The distance here varies directly with time. What is the constant of variation?

telo118 [61]

The distance depends on the time.

So now we need to find the constant of variation or the constant of proportionality.

To do so we must find y(the dependent variable) and x(the independent variable).

To find the constant(k) we must find y/x

Since y/x=k

Then 2.25/.75=k

k=3

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3 years ago

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Y=x7<br><br><br> Please help I really confused

tigry1 [53]

Answer:

Where is the rest of the question? What is it asking?

Step-by-step explanation:

Well I guess if you want to change up the equation you can do 7 * X = Y

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3 years ago

A company sold 3,000 computers in one month, but 12 were returned. If 3,500 were sold the next month, the company would expect 1

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2 years ago

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You have total coins for a total of $. . You only have quarters and dimes. Let represent the number of quarters and represent th

Sonja [21]

Answer:

$Quarters = 41$

$Dimes = 18$

Step-by-step explanation:

Given

$Coins = 59$

$Worth = \$12.05$

$d = dimes$

$q = quarters$

Required

The number of each coin

The total coins can be represented as:

$d + q = 59$

$1\ quarter = \$0.25 \\ 1\ dime = \$0.10$

So, the worth of the coin is:

$0.25q + 0.10d = 12.05$

The equations to solve are:

$0.25q + 0.10d = 12.05$

$d + q = 59$

Make d the subject in: $d + q = 59$

$d =59 - q$

Substitute $d =59 - q$ in $0.25q + 0.10d = 12.05$

$0.25q + 0.10(59 - q) = 12.05$

$0.25q + 5.9 - 0.10q = 12.05$

Collect like terms

$0.25q - 0.10q = 12.05 - 5.9$

$0.15q = 6.15$

Solve for q

$q=\frac{6.15}{0.15}$

$q=41$

Substitute $q=41$ in $d =59 - q$

$d = 59 - 41$

$d = 18$

So:

$Quarters = 41$

$Dimes = 18$

5 0

2 years ago

A square patio has an area of 200 square feet. How long is each side of the patio to the nearest tenth?

Darya [45]

If patio is square it means that area of if is $A=a^2$ where a is one side
Now we can substitute A=200 and solve eq
$a^2=200$
a= $\sqrt{200}$
a=14.1421
Now we are rounding to the nearest tenths
a=14.1 because next number is 4 and is less then 5.
The result is 14.1

6 0

3 years ago