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elena55 [62]
2 years ago
15

Express the trig ratios as fractions in simplest terms.

Mathematics
1 answer:
Jet001 [13]2 years ago
4 0

Answer:

Step-by-step explanation:

SOH CAH TOA

cos K  = 36/48 = 3/4

SIN L = 36/48 = 3/4

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Hope I helped.
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Can someone please help me with this?
MrMuchimi

Answer:

a. 3, 100 degrees

- I know 6 is 100 degrees and angle 3 is identical to angle 6. Therefore, angle 3 is 100 degrees.

b. 6, 100 degrees

- Angle 3 and 6 are identical. This means angle 6 is 100 degrees.

c. 4, 80

- Knowing a straight line is 180 degrees and all other angles are 100 degrees, I subtracted 180-100 = 80 degrees

Step-by-step explanation:

Everything was explained above, but be sure to know...

       N

W             E

       S

- Hope that helps! Please let me know if you need further explanation.

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2 years ago
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Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si
Inessa [10]

Using relations in a right triangle, it is found that:

  • \sin{x} = \frac{6}{10} = 0.6
  • \cos{y} = \frac{6}{10} = 0.6
  • Since x and y are complementary angles, we have that sin(xº) = cos(yº).

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
  • The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
  • The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

The hypotenuse in this problem is given as follows:

h^2 = 6^2 + 8^2

h = \sqrt{100}

h = 10.

The sine of x is:

\sin{x} = \frac{6}{10} = 0.6

The cosine of y is:

\cos{y} = \frac{6}{10} = 0.6

Since x and y are complementary angles, we have that sin(xº) = cos(yº).

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

8 0
2 years ago
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