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cluponka [151]
2 years ago
5

Which choices are equivalent to the quotient below? Check all that apply.

Mathematics
1 answer:
maks197457 [2]2 years ago
5 0

Answer:

C

Step-by-step explanation:

4

_

2 can be multiple by 3 and that will be same as 12

_

6

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Consider the formula for surface area, SA = (p • h) + 2B. The perimeter is
ladessa [460]

Answer:

D

Step-by-step explanation:

Perimeter and height are in inches and area is inches squared

7 0
1 year ago
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A small regional carrier accepted 16 reservations for a particular flight with 12 seats. 8 reservations went to regular customer
wolverine [178]

Answer:

a) 32.04% probability that overbooking occurs.

b) 40.79% probability that the flight has empty seats.

Step-by-step explanation:

For each booked passenger, there are only two possible outcomes. Either they arrive for the flight, or they do not arrive. The probability of a passenger arriving is independent of other passengers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Our variable of interest are the 8 reservations that went for the passengers with a 48% probability of arriving.

This means that n = 8, p = 0.48

A) Find the probability that overbooking occurs.

12 seats, 8 of which are already occupied. So overbooking occurs if more than 4 of the reservated arrive.

P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{8,5}.(0.48)^{5}.(0.52)^{3} = 0.2006

P(X = 6) = C_{8,6}.(0.48)^{6}.(0.52)^{2} = 0.0926

P(X = 7) = C_{8,7}.(0.48)^{7}.(0.52)^{7} = 0.0244

P(X = 8) = C_{8,5}.(0.48)^{8}.(0.52)^{0} = 0.0028

P(X > 4) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.2006 + 0.0926 + 0.0244 + 0.0028 = 0.3204

32.04% probability that overbooking occurs.

B) Find the probability that the flight has empty seats.

Less than 4 of the booked passengers arrive.

To make it easier, i will use

P(X < 4) = 1 - (P(X = 4) + P(X > 4))

From a), P(X > 4) = 0.3204

P(X = 4) = C_{8,4}.(0.48)^{4}.(0.52)^{4} = 0.2717

P(X < 4) = 1 - (P(X = 4) + P(X > 4)) = 1 - (0.2717 + 0.3204) = 1 - 0.5921 = 0.4079

40.79% probability that the flight has empty seats.

4 0
2 years ago
Find each measurement indicated. Round your answers to the nearest tenth. Please show work. Part 1​
timama [110]

9514 1404 393

Answer:

  1. 33.0 m
  2. 26.1 mi
  3. 28.0 mi
  4. 33.0 mi

Step-by-step explanation:

In each of these Law of Sines problems, you are given side a and angles B and C and asked for side c (problems 1, 3, 4) or side b (problem 2). The solution is basically the same for each:

Find the missing angle. Find the side from ...

  c = a·sin(C)/sin(A)

__

1. angle A = 180°-89°-58° = 33°

  c = (18 m)sin(89°)/sin(33°) ≈ 33.0 m

__

2. angle C = 180°-13°-17° = 150°

  b = (58 mi)sin(13°)/sin(150°) ≈ 26.1 mi

__

3. angle A = 180°-61°-89° = 30°

  c = (16 mi)sin(61°)/sin(30°) = 28.0 mi

__

4. angle A = 180°-39°-127° = 14°

  c = (10 mi)sin(127°)/sin(14°) ≈ 33.0 mi

7 0
3 years ago
Simplify<br> (5a2bc3) abc4
Tatiana [17]
(5a^{2}bc^{3}) abc^{4}=5*(a^{2}*a)*(b*b)*(c^{3}*c^{4})=5*a^{3}*b^{2}*c^{7}\\\\&#10;5a^{3}b^{2}c^{7}\ is\ your\ answer.
5 0
3 years ago
Can u guys help me with this show all work that is the main thing
pochemuha
12x7x3=Volume recipe, the dirt they have to remove is within that volume so just do that formula and bam you got your answer
6 0
3 years ago
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