Answer:
-3 5/12=k
Step-by-step explanation:
K+5/3= -7/4
subtract 5/3 from both sides
K= -7/4-5/3
lcm of 4 and 3 is 12
so
K= -21/12-20/12
K= -41/12
K= -3 5/12
105 x 0.08 and what you get is your answer
Solving:
-7 + y = 3 + 2y
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '-2y' to each side of the equation.
-7 + y + -2y = 3 + 2y + -2y
Combine like terms: y + -2y = -1y
-7 + -1y = 3 + 2y + -2y
Combine like terms: 2y + -2y = 0
-7 + -1y = 3 + 0
-7 + -1y = 3
Add '7' to each side of the equation.
-7 + 7 + -1y = 3 + 7
Combine like terms: -7 + 7 = 0
0 + -1y = 3 + 7
-1y = 3 + 7
Combine like terms: 3 + 7 = 10
-1y = 10
Divide each side by '-1'.
y = -10
Hope it helps. (:
Answer:
B
Step-by-step explanation:
For a relationship to be a function
Each value of x in the domain can only have 1 unique value of y in the range. That is, one-to-one correspondence.
The only relation which meets this criteria is B
Step-by-step explanation:
the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).
I think your teacher made a mistake, or you made one when typing the question in here.
there is no factor r that creates
15×r = 9
and
9×r = 5/27
it would mean that
15 × r² = 5/27
r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81
r = 1/9
but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9
and 9 × 1/9 = 9/9 = 1 is NOT 5/27
so, this can't be right.
on the other hand
15 × r = 9
r = 9/15 = 3/5
and then
9 × 3/5 = 27/5
so, either the sequence should have been
15, 5/3, 5/27
or (and I suspect this to be true)
15, 9, 27/5
under that assumption we have
s1 = 15
r = 3/5
sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)
s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =
= 3 × 19683/390625 = 59049/390625 =
= 0.15116544 ≈ 0.151
