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2 years ago

100 POINTS PLEASE HELP

Computers and Technology

2 answers:

Oksana_A [137]2 years ago

6 0

Answer:

hope this helped ,do consider giving brainliest

Explanation:

import numpy as np

#PrintArray Function

def printArray(array):

for i in range(len(array)):

for j in range(len(array[i])):

print(array[i][j], end= " ")

print()

#Flip horizontal function

def flipHorizontal(array):

#reversing the order of arrays

array2 = np.fliplr(array).copy() printArray(array2)

#Flip Vertical function

def flipVertical(array):

#Preserving the order of array and reversing each array.

array3 = np.flipud(array).copy() printArray(array3)

#Main() function def main():

array = [[0,2,0,0,0],[0,2,0,0,0],[0,2,2,0,0],[0,2,0,2,0],[0,2,0,0,2]]

print("The array: \n")

printArray(array)

print("\nFlipped horizontally: \n") flipHorizontal(array)

print("\nFlipped vertically: \n") flipVertical(array)

if __name__=="__main__":

main()Explanation:

telo118 [61]2 years ago

5 0

Answer:

Answer:

hope this helped ,do consider giving brainliest

Explanation:

import numpy as np

#PrintArray Function

def printArray(array):

for i in range(len(array)):

for j in range(len(array[i])):

print(array[i][j], end= " ")

print()

#Flip horizontal function

def flipHorizontal(array):

#reversing the order of arrays

array2 = np.fliplr(array).copy() printArray(array2)

#Flip Vertical function

def flipVertical(array):

#Preserving the order of array and reversing each array.

array3 = np.flipud(array).copy() printArray(array3)

#Main() function def main():

array = [[0,2,0,0,0],[0,2,0,0,0],[0,2,2,0,0],[0,2,0,2,0],[0,2,0,0,2]]

print("The array: \n")

printArray(array)

print("\nFlipped horizontally: \n") flipHorizontal(array)

print("\nFlipped vertically: \n") flipVertical(array)

if __name__=="__main__":

main()Explanation:

Explanation:

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irga5000 [103]

Answer:

Following are the code in the C programming Language.

//define function

void duplicate(char*argv, char**result) {

//set and initialize the variable to 0

int c = 0;

//set and initialize the char type pointer variable

char** t = argv;

//set the while loop

while(t){

//increment by 1

c++;

//increment by 1

t++;

}

//set malloc function in the pointer variable

result= malloc(sizeof(char)*(c+1));

//set the for loop

for(int i = 0; i < c; i++) {

//set malloc function in the pointer

(*result)[i] = malloc(strlen(argv[i])+1);

//copy the character from memory

memcpy(argv[i], (*result)[i], strlen(argv[i])+1) ;

}

//initialize null in the pointer

(*result)[i] = NULL;

}

Explanation:

In the following code, we define function "duplicate()" and pass two character type pointer arguments "*argv" and "**result" and inside the function.

Set an integer type variable "c" and initialize to 0.
Set character type pointer variable "t" and initialize the value of pointer variable "argv".
Set the while loop and increment in the variable "c" and "t" by 1.
Set the malloc function in the pointer variable "result".
Set the for loop to copy the character from the memory.
Finally, initialize the pointer variable "result" to NULL.

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Explanation:

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4 years ago

Implement the following logic in C++, Use appropriate data types. Data types are represented as either numeric (num) or string.

ICE Princess25 [194]

Answer:

Follows are the modified code in c++ language:

#include<iostream>//header file

#include<string>//header file

using namespace std;

int main()//main method

{

string name,address, MSG_YES, MSG_NO;//defining string variable

int item,quantity,size=6, i=0;//defining integer variable

double price;//defining double variable

int VALID_ITEM[]={106,108,307,405,457,688};//defining integer array and assign value

double VALID_ITEM_PRICE[]={0.59,0.99,4.50,15.99,17.50,39.00};//defining double array and assign value

bool foundIt=false;//defining bool variable

MSG_YES="Item available";//use string variable to assign value

MSG_NO = "Item not found"; //use string variable to assign value

cout<<"Input name: ";//print message

cin>>name;//input value in string variable

cout<<"Input Address: ";//print message

cin>>address;//input value in string variable

cout<<"Input Item: "<<endl;//print message

cin>>item;//input value in string variable

cout<<"Input Quantity: "<<endl;//print message

cin>>quantity;//input value in string variable

while(i <size)//defining while that checks i less then size

{

if (item ==VALID_ITEM[i]) //use if block to match item in double array

{

foundIt = true;//change bool variable value

price = VALID_ITEM_PRICE[i];//hold item price value in price variable

}

i++;//increment the value of i

}

if (foundIt == true)//use if to check bool variable value equal to true

{

cout<<MSG_YES<<endl;//print value

cout<<"Quantity "<<quantity<<" at "<<"Price "<<price<<"each"<<endl;//print value

cout<<"Total"<<quantity*price;//calculate the total value

}

else//else block

cout<<MSG_NO;//print message

}

Output:

please find the attached file.

Explanation:

In the above given C++ language modified code, four-string variable " name, address, MSG_YES, and MSG_NO", four integer variable "item, quantity, size, and i", and "integer and double" array is defined, that holds values.

In the string and integer variable "name, address, and item, quantity", we input value from the user-end and use the while loop, which uses the if block to check the "item and quantity" value from the user end and print its respective value.

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