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Marizza181 [45]
1 year ago
11

Find the first derivative of x^2+y^2=25​

Mathematics
1 answer:
lozanna [386]1 year ago
4 0

Answer:

\frac{dy}{dx}=-\frac{x}{y}

Step-by-step explanation:

Use implicit differentiation:

x^2+y^2=25\\\\2x+2y\frac{dy}{dx}=0\\ \\2y\frac{dy}{dx}=-2x\\ \\\frac{dy}{dx}=-\frac{x}{y}

Remember to treat "y" as a constant in implicit differentiation and include dy/dx.

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Volgvan

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x ≤ 2

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We are given the inequality:

\displaystyle{2x-3 \leq \dfrac{x}{2}}

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\displaystyle{2x\cdot 2-3\cdot 2 \leq \dfrac{x}{2}\cdot 2}\\\\\displaystyle{4x-6 \leq x}

Add both sides by 6 then subtract both sides by x:

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Then divide both sides by 3:

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Read 2 more answers
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