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3 years ago

How do we figure this out

Mathematics

1 answer:

lisov135 [29]3 years ago

8 0

Answer:

Pair 1: 10 cm and 2 cm. and the sum is 12 cm.

Pair 2: 20 cm and 4 cm. and the sum is 24 cm.

Step-by-step explanation:

Area of a rectangle is given by A = LW, where L is the length and W is the width of the rectangle.

Pair 1:

For the first rectangle W = 4 cm and A = 40 sq, cm

Then $L = \frac{A}{W} = \frac{40}{4} = 10$ cm.

For the second rectangle W = 4 cm and A = 8 sq, cm

Then $L = \frac{A}{W} = \frac{8}{4} = 2$ cm.

Therefore, the sum of two unknown lengths = 10 + 2 = 12 cm. (Answer)

Pair 2:

For the first rectangle W = 4 cm and A = 80 sq, cm

Then $L = \frac{A}{W} = \frac{80}{4} = 20$ cm.

For the second rectangle W = 4 cm and A = 16 sq, cm

Then $L = \frac{A}{W} = \frac{16}{4} = 4$ cm.

Therefore, the sum of two unknown lengths = 20 + 4 = 24 cm. (Answer)

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3 years ago

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2 years ago

What is -1/2 + n = -5/8 what does n equal

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3 years ago

Please help! I don't understand how to solve this problem

Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

$S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547$

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

$M = z\frac{\sigma}{\sqrt{n}}$

$0.006 = 1.96\frac{1.1547}{\sqrt{n}}$

$0.006\sqrt{n} = 1.96 \times 1.1547$

$\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}$

$(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2$

n = 142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0

1 year ago