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PilotLPTM [1.2K]
2 years ago
8

Solve each pair of simulation equation.Giving both solutions. Multiply both equations by suitable numbers before adding/subtract

ing to elimination..
A) 6x-7y=9
3x+2y=54



B) 4x -5y =12
2x -3y =8


C)4x -2y=28
3x +3y=12


D)2x +5y =14
13x-11y=-83​
Mathematics
1 answer:
pashok25 [27]2 years ago
6 0

Answer:

Step-by-step explanation:

I haven't got time to do all these by I'll give you the method in each case.

You have to make the x or y term equal (or 1 term + and other -) in both equations before adding or subtracting.

A . Multiply  equation 2 by 2 and subtract (to eliminate x)

- don't forget to multiply EACH TERM by 2.

B. Multiply  equation 2 by -2 and add.

C.  Multiply  equation 1 by 3 and equation 2 by 2 ( this will give -6y and +6y in the resulting equations ) so  you then add to eliminate y.

D.  Multiply equation 1 by 13 and equation  and equation 2 by 2 to eliminate x then add.

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The slope and length of the given sides of the quadrilateral can be

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Correct responses:

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<h3>Methods used to find the slope and length of a line</h3>

The given coordinates of the vertices are;

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  • Slope = \mathbf{\dfrac{y_2 - y_1}{x_2 - x_1}}

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Therefore;

Slope \ of \ \mathbf{\overline{IJ}} = \dfrac{-2 - (-9)}{2 - 8} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length \ of \ \mathbf{\overline{IJ}} = \sqrt{(2 - 8)^2 + (-2 - (-9))^2} = \underline{\sqrt{85}}

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Slope \ of \ \mathbf{\overline{KL}} = \dfrac{0 - (-7)}{-7 - (-1)} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length  \ of \ \mathbf{\overline{KL} }= \sqrt{(-7 - (-1))^2 + (0 - (-7))^2} =\underline{ \sqrt{85}}

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Length \ of \ \mathbf{\overline{LI}} = \sqrt{(8 - (-1))^2 + (-9 - (-7))^2} = \underline{\sqrt{85}}

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