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3 years ago

14

Independent Practice

1 answer:

gladu [14]3 years ago

4 0

Answer:

D.

d = 3t; 90 mi

Step-by-step explanation:

Bicycling A bicyclist traveled at a constant speed during a timed practice period. Write a proportion to find the distance the cyclist traveled in 30 min.

elapsed time distance

10 min 3 mi

25 min 7.5 mi

Graph it. :)

Start at (0,0), then at 10 min. on the x-axis, go 3 spaces up on the y-axis and plot a point. Do the same for 25 min. and 7.5 miles. Draw a line through all of those points, and see where the line hits on the y-axis when the x-axis is at 30 min. :)

If two things vary directly it means their ratio is a constant. Therefore from the formula rt=d. r=d/t, r=3/10 or 7.5/25 which reduces to 3/10. This is the constant speed,the lable is mi/min. Now use (d/30)=(3/10) and solve for d. Cross multiply and 10d=90, or d=9 mi

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What is the order of steps to calculate the volume of prime?

Vlad1618 [11]

Answer

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Step-by-step explanation:

7 0

2 years ago

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

irakobra [83]

Answer: Car B traveled 60 mph.

Step-by-step explanation:

A= B-15

A: (B - 15)(2 hr)=D

B: (B)(1.5)=D

Since B and A traveled the same distance you can plug in 1.5B for D.

2B - 30 = 1.5B

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——————+30—

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4 0

2 years ago

Read 2 more answers

Can someone please help me in this question.

mestny [16]

Answer:

a) $2^{3}$

b) $2^{5}$

c) $2^{8}$

d) $\frac{5}{2^{3} }$

e) $2^{4} + 2^{3}$

Step-by-step explanation:

a) 8 = 2 x 2 x 2

b) 32 = 2 x 2 x 2 x 2 x 2

c) 256 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

d) 5 x 2^3 / 64 = 5 x 8 / 64

= 40/64

= 5/8

= $\frac{5}{2^{3} }$

e) 16 - (-2)^3 = 16 - (-8)

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2 years ago

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Serhud [2]

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2 years ago

You could win a giant jar of M&Ms, if only you could guess how many are in the jar. You find a smallerjar such that the gian

sleet_krkn [62]

Answer:

There are 7360 M&Ms in larger jar.

Step-by-step explanation:

We are given the following in the question:

A giant jar is such that it is exactly four times times the smaller jar in dimensions.

If r and h is the radius and height of the cylindrical jar respectively, then the dimensions of the larger are:

$R = 4r\\H=4h$

Number of M&Ms in smaller jar = 115

Volume of smaller jar =

$v = \dfrac{1}{3}\pi r^2 h$

Volume of larger jar =

$V =\dfrac{1}{3}\pi R^2 H=\dfrac{64}{3}\pi r^2 h$

Number of M&Ms in larger jar:

$v = \dfrac{1}{3}\pi r^2 h\rightarrow 115\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 115\times 64\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 7360$

Thus, there are 7360 M&Ms in larger jar.

6 0

3 years ago