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mote1985 [20]
3 years ago
14

Independent Practice

Mathematics
1 answer:
gladu [14]3 years ago
4 0

Answer:

D.

d = 3t; 90 mi

Step-by-step explanation:

Bicycling A bicyclist traveled at a constant speed during a timed practice period. Write a proportion to find the distance the cyclist traveled in 30 min.

elapsed time    distance

10 min               3 mi

25 min               7.5 mi

Graph it. :)

Start at (0,0), then at 10 min. on the x-axis, go 3 spaces up on the y-axis and plot a point. Do the same for 25 min. and 7.5 miles. Draw a line through all of those points, and see where the line hits on the y-axis when the x-axis is at 30 min. :)

If two things vary directly it means their ratio is a constant.  Therefore from the formula rt=d. r=d/t,  r=3/10 or 7.5/25  which reduces to 3/10.  This is the constant speed,the lable is mi/min.  Now use  (d/30)=(3/10)  and solve for d.  Cross multiply and 10d=90, or d=9 mi

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What is the solution to the equation -3d/a^2-2d-8 + 3/d-4 = -2/ d+2
Alex73 [517]

Answer:

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Step-by-step explanation:

\frac{-3d}{d^2-2d-8} +\frac{3}{d-4} =\frac{-2}{d+2}

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3 0
3 years ago
Read 2 more answers
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