The greatest whole possible whole number length of the unknown side is 9 inches.
<h3>How to identify if a triangle is acute?</h3>
Let us have:
H = biggest side of the triangle
And let we get A and B as rest of the two sides.
Then we get:
If

then the triangle is acute
Two sides of an acute triangle measure as 5 inches and 8 inches
The length of the longest side is unknown.
We have to find the length of the unknown side
WE know that the longest side of any triangle is a hypotenuse
For an acute triangle we know:

Here in this sum,
a = 5 inches
b = 8 inches
c = ?
Substituting we get,

c < 9
Hence, The greatest whole possible whole number length of the unknown side is 9 inches.
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Answer:
A) ERROR
B) ∠C = 26°
Step-by-step explanation:
Houston, We have a problem!!! too much information
If we had a legit triangle, the law of sines would hold
19/sin138 = 8/sin20
28.395 = 23.390
as this is NOT an equality, the triangle does not exist as described.
IF it did, we'd get different results depending on which set we used
∠F = 180 - 138 - 20 = 22°
Law of sines
19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>
or
8/sin20 = DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>
If we attempt to use Law of cosines
DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>
so really none is correct because we attempt to use trig calculations to a non-triangle.
12) AC² = 15² + 19² - 2(15)(19)cos120
AC = 29.51270...
29.51270 / sin120 = 15/sinC
C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>
Here is how to do the question,
The Remainder Theorem starts with an unnamed polynomial p(x), where "p(x)" just means "some polynomial p whose variable is x". ... If you get a remainder, you do the multiplication and then add the remainder back in. For instance, since 13 ÷ 5 = 2 R 3, then 13 = 5 × 2 + 3. This process works the same way with polynomials.
Hope that helps!!!!
Answer:
H
Step-by-step explanation:
I have done the work before