Find the value of x. log x 8 = 0.5 ОА. 4. OB. 16 O C. 32 OD. 64

Mathematics

1 answer:

Zanzabum2 years ago

6 0

Answer:

The answer to your question is D 64

Step-by-step explanation:

hope this helps you have a wonderful day.

You might be interested in

Why does a negative times a negative equal a positive proof?

lisov135 [29]

Because two negatives cancel each other out, resulting in a positive.

6 0

3 years ago

Read 2 more answers

Latavia purchased adult and child tickets for the fall festival. Tickets cost $14.88 for each adult and $8.88 for each child. Le

nika2105 [10]

Answer:

14.88x + 8.88y =

Step-by-step explanation:

This may be wrong but I think it’s this

3 0

3 years ago

Read 2 more answers

100000 less than 560313 is

arsen [322]

100000
-560313

460313

3 0

3 years ago

Can someone please help me

nadya68 [22]

Answer:

Right option is B.

Step-by-step explanation:

$\sf \longrightarrow \frac{ \sec x \sin( - x) + \tan( - x) }{1 + \sec( - x) } \\ \\ \sf \longrightarrow \frac{ \sec x( - \sin x) - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \frac{1}{ \cos x } \times \sin x - \tan x }{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \tan x - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - 2 \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{1 + \frac{1}{ \cos x} } \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} } \\ \\ \boxed{ \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1} }}$

4 0

1 year ago

The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches What is the height of the tr

ExtremeBDS [4]

The height of the triangular base of the pyramid is calculated through the equation,
h = (cos x)(18 in)
where h is height and x is half of the angle of the triangle. Since the triangle is equilateral, the value of x is 30°. Substituting,
h = (cos 30°)(18 in)
h = 15.59 in
Thus, the height of the base is approximately 15.59 inches.

6 0

3 years ago

Read 2 more answers