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goblinko [34]
2 years ago
6

The radius of a cylindrical construction pipe is 2 ft. If the pipe is 24 ft long, what is its volume?

Mathematics
1 answer:
VARVARA [1.3K]2 years ago
5 0

Answer:

96π ft³ or 301.44 ft³

Step-by-step explanation:

Volume = Base Area x Height

V = (πr²)(h)

V = (π)(2²)(24)

V= 96π ft³

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Will give brainliest
kodGreya [7K]

Answer: y=12 x =9

Step-by-step explanation:

In a parallelogram the diagonals bisect each other making them equal.

this means 2y + 6 = 30

we can rearrange this as 30 - 6 = 2y

24 = 2y  therefore y = 12

3x - 3 = 24

We can rearrange this as 24 + 3 = 3x

3x = 27

27 / 3 = 9

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Answer:

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2 years ago
A recent estimate by a large distributor of gasoline claims that 60% of all cars stopping at their service stations chose unlead
Anton [14]

Answer:

We reject the null hypothesis and conclude that at least 2 proportions differ from the stated value.

Step-by-step explanation:

There are 3 types of gas listed in the question.

Thus;

n = 3

DF = n - 1

DF = 3 - 1

DF = 2

Let's state the hypotheses;

Null hypothesis; H0: P_regular = P_super unleaded = 20%; P_i leaded = 60%

Alternative hypothesis; Ha: At least 2 proportions differ from the stated value.

Observed values are;

Regular gas; O = 51

Unleaded gas; O = 261

Super Unleaded; O = 88

Total observed values = 51 + 261 + 88 = 400

We are told that super unleaded and regular were each selected 20% of the time and that unleaded gas was chosen 60% of the time.

Thus, expected values are;

Regular gas; E = 20% × 400 = 80

Unleaded gas; E = 60% × 400 = 240

Super Unleaded; E = 20% × 400 = 80

Formula for chi Square goodness of fit is;

X² = Σ[(O - E)²/E]

X² = (51 - 80)²/80) + (261 - 240)²/240) + (88 - 80)²/80)

X² = 13.15

From the chi Square distribution table attached and using; DF = 2 and X² = 13.15, we can trace the p-value to be approximately 0.001

Also from online p-value from chi Square calculator attached, we have p to be approximately 0.001 which is similar to what we got from the table.

Now, if we take the significance level to be 0.05, it means the p-value is less than it and thus we reject the null hypothesis and conclude that at least 2 proportions differ from the stated value.

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