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3 years ago

Y = {x-5?

Mathematics

1 answer:

oee [108]3 years ago

7 0

Answer:

The third option, 1/2..

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A bin of 50 manufactured parts contains 3 defective parts and 47 non-defective parts. A sample of size 6 parts is selected from

lyudmila [28]

Answer:

535,095 different samples of size six that contain exactly 2 defective parts.

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

As the order of the parts is not important, the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many different samples are there of size six that contain exactly 2 defective parts?

2 defective from a set of 3, and 4 non-defective from a set of 47. So

$D = C_{3,2}*C_{47,4} = \frac{3!}{2!1!}*\frac{47!}{4!43!} = 535095$

535,095 different samples of size six that contain exactly 2 defective parts.

What is the probability that a sample contains exactly 2 defective parts?

The total number of samples is:

$T = C_{50,6} = \frac{50!}{6!44!} = 15890700$

Then...

$p = \frac{D}{T} = \frac{535095}{15890700} = 0.0337$

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

8 0

3 years ago

Which of the ten basic functions in

storchak [24]

Step-by-step explanation:

Which of the ten basic functions in

our toolkit have an infinite number of

local extrema?

a) cos(x), 2

b) sin(x), cos(x)

c) In(x), cos(x)

d) sin(x), x2

8 0

2 years ago

4/5 equals how many 100th

victus00 [196]

80/100 also eighty out of a hundred.

7 0

3 years ago

How do I do this homework

Vladimir [108]

That's really hard homework I really have never seen anything like that but I'll ask my sister.

7 0

3 years ago

What mathematics concepts or principles did you apply to come up with the solution of each equation? explain how you applied the

AlexFokin [52]

You need to look at the question again, and notice the words "... did you ...".
From those words, it's clear that the question comes AFTER you have solved
several equations, and now, this question is asking you how you solved them.

The only way for YOU to answer this question is to solve the equations first.

And if you want someone ELSE to tell the math concepts and principles that
are used to solve them, then you have to show him what the equations are.

8 0

4 years ago