This question is incomplete, the complete question is;
X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)
Answer:
P( W> 10) is 0.1587
Step-by-step explanation:
Given that;
X ⇒ N( 13.9, 5.2 )
Y ⇒ N( 6.9, 3.8 )
W = X - Y
Therefore
E(W) = E(X) - E(Y)
= 13.9 - 6.9 = 7
Var(W) = Var(X) + Var(Y) -2COV(X.Y)
[ COV(X,Y) = 0 because they are independent]
Var(W) = 5.2 + 3.8 + 0
= 9
Therefore
W ⇒ N( 7, 9 )
so
P( W > 10 )
= 1 - P( W ≤ 10 )
= 1 - P( W-7 /3 ≤ 10-7 /3 )
= 1 - P( Z ≤ 1 ) [ Z = W-7 / 3 ⇒ N(0, 1) ]
from Standard normal distribution table, P( Z ≤ 1 ) = 0.8413
so
1 - P( Z ≤ 1 ) = 1 - 0.8413 = 0.1587
Therefore P( W> 10) is 0.1587
Answer:A ( Both the domain and range of the transformed function are the same as those of the parent fuction
Step-by-step explanation: yes.
I believe the answer is J (both equal to and less than)
Explanation:
X= 4 3(4)= 12 which is less than 18
X= 5 3(5)= 15 which is less than 18
X= 6 3(6)= 18 which is equal to 18
Answer:
x < 2
Step-by-step explanation:
-x + 8 > 6 is our equation.
We can subtract 8 from both sides:
-x > -2
Then, we can flip the inequality sign so that it is positive:
(multiply both sides by -1)
(-x) (-1) < (-2)(-1)
Simplifying gives our answer of:
x < 2
Answer:
Use pemdas
Step-by-step explanation:
Paranthese, e, multiplacation, division, addition, subtraction
