(3n-10p)^2
=(3n-10p)(3n-10p)
=9n^2-10p-10p+100p^2
=9n^2-20p+100p^2
Total = 36oz
Amount of 18% solution = x
Amount of 9% solution = 36 - x
Using the fact that (amount of solution) * (percent HCl) = amount HCl we can set up an expression for the amount HCl in a mixture of 18% and 9% solutions with a total volume of 36oz.
Amount of HCl = x*0.18 + (36 - x)*0.09
If we divide this by the amount of solution we get percent HCl, and we have a target of 10% HCl. Now we have an equation to solve,
[x*0.18 + (36 - x)*0.09]/36 = 0.1
x*0.09 + 3.24 = 3.6
.09x = 0.36
x = 4
Therefore,
4 ounces of 18% HCl solution and 32 ounces of 9% HCl solution
Check:
[(4*.18) + (.09*32)]/36 = 0.1?
0.1 = 0.1 Yes.
Answer:
27
Step-by-step explanation:
5y-2z
1.plug in
5(8)-2(9)
2.solve
5(8)=45
3.solve
2(9)=18
4.subtract
45-18=27
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answered by aurinda
hope it helps:)
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Answer:
She didn't take the LCM, made an error while cross multiplying
x = -6
Step-by-step explanation:
a)she didn't take the LCM before cross multiplying.
Also, didn't cross multiply correctly
b) 1 -2/(x-2) = (x+1)/(x+2)
1 - 2/(x-2) = (x+2-1)/(x+2)
1 - 2/(x-2) = 1 - 1/(x+2)
1 - 2/(x-2) = 1 - 1/(x+2)
-2(x+2) = -1(x-2)
-2x-4 = -x+2
x = -6
