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2 years ago

Unit 4: Congruent Triangles Homework 2: Angles of Triangles

1 answer:

5 0

The value of the third angle that can be found in the information given about the congruent triangles will be 45°.

<h3>How to solve the triangle?</h3>

From the complete information, the angles that are given in the triangle are 76° and 59°.

It should be noted that the value of the total angles that are in a triangle is 180°. Therefore, the value of the last angle will be:

= 180° - (76° + 59°)

= 180° - 135°

= 45°

Learn more about triangles on:

brainly.com/question/17335144

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An artist creates a cone-shaped sculpture for an art exhibit. If the sculpture is 8 feet tall and has a

nikitadnepr [17]

Answer:

192.92 ft^3

Step-by-step explanation:

volume of a cone = $\frac{1}{3}$ πr²h

π = 3.14

r = radius ]

h = height

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Step-by-step explanation:

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4 years ago

If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime

Yuri [45]

Answer:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

Step-by-step explanation:

Given two positive integers $r$ and $s$ .

To check whether $\small \frac{r}{s}$ is an integer:

Condition (1):

Every factor of $s$ is also a factor of $r$ .

$r \geq s$

Let us consider an example:

$s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2$

$\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10$

which is an integer.

Actually, in this situation $s$ is a factor of $r$ .

Condition 2:

Every prime factor of s is also a prime factor of r.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

$r = 2^2\cdot 5\\s =2^4\cdot 5$

$\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}$

which is not an integer.

So, the answer is:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

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3 years ago