The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)
taking another point (-1,5)
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)
b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1
Step-by-step explanation:
-16 + 3n = - 8 - 5n
Bringing like terms on one side
3n + 5n = - 8 + 16
8n = 8
n = 8/8
N = 1
Answer: 200x^2y+640x^2+1010xy+3232x-2380y-7616
Step-by-step explanation:
((8x−14)(5y+16))(5x+34)
((8x−14)(5y+16))(5x)+((8x−14)(5y+16))(34)
200x2y+640x2−350xy−1120x+1360xy+4352x−2380y−7616
200x2y+640x2+1010xy+3232x−2380y−7616
Use photomath bc that app always helps
3.17 x 10^5 = <span>317000</span>
