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Sergeeva-Olga [200]
2 years ago
6

Carly and Carter are comparing bedrooms. They are each getting new carpet and are trying to figure out which room will be the mo

st expensive to cover with carpet. (The rooms are both rectangular) Carly's bedroom is 15.3 ft. long and 8.7 ft. wide. Carter's bedroom is 14.4 ft. long and 9.6 ft. wide. Which bedroom will be the most expensive to cover with carpet? Explain your steps for figuring out the area of the floor for each bedroom and determining your answer. Make sure to Show your math steps as well.
Mathematics
2 answers:
Yanka [14]2 years ago
8 0

Answer:

<h2> carter bedroom has most expensive </h2>

Step-by-step explanation:

<h2>first we solve carly </h2>

<h2>carly bedroom is 15 •3 ft </h2>

<h2>and its wide = 8 •7 </h2>

<h2>so ,,</h2>

<h2>15•3 x 8 •7 </h2>

<h2>= 133 • 11</h2><h2>it's is area of carly bedroom </h2>

<h2> carter bedroom we solve </h2>

<h2>length = 14 •4 </h2>

<h2>wide = 9 •6 </h2>

<h2>14 •4 x 9 • 6 </h2>

<h2>138 • 24 is area of carter </h2>

Softa [21]2 years ago
5 0

Answer:

Carter's bedroom would cost more to carpet than Carly's because the floor area of the former is about five square feet greater than the floor area of Carly's bedroom.

Step-by-step explanation:

The area of either of these floors is found by multiplying length by width:

A = L*W.

Carly's bedroom is 15.3 ft by 8.7 ft; multiplying, we get A = 133.11 ft^2

Carter's is 14.4 ft by 9.6 ft:  A = 138.24 ft^2

Carter's bedroom area (138.24 ft^2) is about 5 ft^2 larger than Carly's and would thus cost more to carpet.

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