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2 years ago

How to find a polynomial function with given zeros.

Mathematics

1 answer:

Finger [1]2 years ago

7 0

First of all,

let the two zeroes be 2 and 3.

Now,

Sum of the zeros = 2 + 3 = 5

Product of the zeros = 2 × 3 = 6

Hence, the polynomial formed is,

= x² – (sum of zeros)x + Product of zeros

= x² – 5x + 6

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

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3.3

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2 years ago

Find the solution of the differential equation that satisfies the given initial condition. dy/dx=x/y , y(0)=-1

Charra [1.4K]

Separating variables, we have

$\dfrac{dy}{dx} = \dfrac xy \implies y\,dy = x\,dx$

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$\displaystyle \int y\,dy = \int x\,dx$

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Given that $y(0)=-1$ , we find

$\dfrac12 (-1)^2 = \dfrac12 0^2 + C \implies C = \dfrac12$

Then the particular solution is

$\dfrac12 y^2 = \dfrac12 x^2 + \dfrac12$

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$y = \pm\sqrt{x^2 + 1}$

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$\boxed{y(x) = -\sqrt{x^2+1}}$

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2 years ago

B) Solve<br> (i)<br> 9x = 36

Vaselesa [24]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers