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kkurt [141]
2 years ago
12

PLEASE HELP 100 POINTS AND BRAINLY

Mathematics
2 answers:
gregori [183]2 years ago
7 0

Answer:

Step-by-step explanation:

dem82 [27]2 years ago
6 0

Answer:

(2 , 2) is the solution

Step-by-step explanation:

7x - 4y = 6

-6x + 7y = 2

49x - 28y = 42

-24x + 28y = 8

25x = 50

therefore

<u>x = 2</u>

7x - 4y = 6

7×2 - 4y = 6

14 - 4y = 6

14 - 6 = 4y

8 = 4y

8 ÷ 4 = 4y ÷ 4

<u>2 = y</u>

therefore

x = 2

y = 2

hope this will helpful to you....

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The sum of two numbers is 22, and their difference is 12. What are the numbers?
Shkiper50 [21]

Answer:

the anwser is 10 and 12

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8 0
3 years ago
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Ashton rode his bicycle 3.25 miles in 12 minutes. What was Ashton’s average rate in miles per hour?
dangina [55]

Answer:

Ashton rode his bicycle 3.25 miles in 12 minutes. What was Ashton's average rate in miles per hour? The answer is 16.25

Ive done this

7 0
3 years ago
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. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?
UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u>As we know:</u>

<u />Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \  of\ I-pad}

5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2

a) Thus, the total width of the I-Pads are 61.2 inches.

Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \  of\ Kindles}

4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles \div Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = \frac{99.6}{20} =4.98\ inches

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

5 0
3 years ago
supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are
Simora [160]
<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu

, where n= sample size

\overline{x} = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : df=n-1=24

\overline{x}= \$93.36

s=\ $19.95

Significance level for 98% confidence interval : \alpha=1-0.98=0.02

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu

=93.36-9.943878< \mu

=93.36-9.943878< \mu

=83.416122< \mu

Hence, the 98% confidence interval for the mean repair cost for the dryers. = 83.4161

4 0
3 years ago
15 points. Please help meeee
yaroslaw [1]

Answer:

B.

Step-by-step explanation:

5 0
3 years ago
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