What is the electoral college? select one:

Mathematics

1 answer:

ad-work [718]3 years ago

8 0

The answer is "electors from each state who cast ballots for president and vice president."

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Please help me. I don’t know how to do this I really need this answer.

Ainat [17]

The answer is c.
I will explain

p - 2r = q

1. Move variable to the right by adding it’s opposites on both sides

p - 2r + 2r = q + 2r

2. Eliminate the opposites (-2r and +2r)

p = q + 2r

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3 years ago

Solve the equation. x-5(x-1)=x-(2x-3)

levacccp [35]

Answer: x=2/3

Step-by-step explanation:

7 0

3 years ago

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Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

Agata [3.3K]

$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------$

$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o$

8 0

3 years ago

Which values are solution to the inequality below? check all that apply.

xxTIMURxx [149]

A,E,F
Sq rt of 25 is 5 and 5 is less than 10
Sq rt of 36 is 6 and 6 is less than 10
Sq rt of 9 is 3 and 3 is less than 10

3 0

3 years ago

Given the graph below, which of the following statements is true?

Nesterboy [21]

To be a function, it has to pass the vertical line test, which means a vertical line drawn anywhere in the graph should cut the graph only once, not more.

To be a one-to-one function, it has to pass the vertical line test as well as the horizontal line test, which means that a horizontal line drawn anywhere in the graph should cut the graph only once, not more.

Of course, it passes the vertical line test, so its a function.

Does it pass the horizontal line test? NO! As shown in the attached picture, the blue line (horizontal line) cuts the graph at 3 places. We therefore eliminate choices A and B. We can eliminate choice C because nowhere is it required a function to pass through the origin for it to be one-to-one. Hence, the answer is D (blue line shows this).

ANSWER: D

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3 years ago

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