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3 years ago

What is the electoral college? select one:

Mathematics

1 answer:

ad-work [718]3 years ago

8 0

The answer is "electors from each state who cast ballots for president and vice president."

Have a great night! :)

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How many triangles exist with the given side lengths of 3cm, 5cm, and 9cm?

Irina-Kira [14]

Only one triangle exist

3 0

4 years ago

Read 2 more answers

Write the linear eqaution in slope form for x and y. 1/3x+y=-2

Anit [1.1K]

Answer:

y = -1/3x -2

Step-by-step explanation:

Slope intercept form of a line is

y= mx+b

We need to solve for y

1/3x +y = -2

Subtract 1/3x from each side

1/3x -1/3x +y =-1/3x -2

y = -1/3x -2

4 0

3 years ago

Is (3, 28) a solution to 4x-y=-16

d1i1m1o1n [39]

Answer:

Yes

Step-by-step explanation:

4(3) - 28 = -16

12= -16 + 28

12 = 12

Hope that helps!

4 0

3 years ago

Use mathematical induction to prove the statement is true for all positive integers n. 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = (n(2n-

Charra [1.4K]

Answer:

The statement is true is for any $n\in \mathbb{N}$ .

Step-by-step explanation:

First, we check the identity for $n = 1$ :

$(2\cdot 1 - 1)^{2} = \frac{2\cdot (2\cdot 1 - 1)\cdot (2\cdot 1 + 1)}{3}$

$1 = \frac{1\cdot 1\cdot 3}{3}$

$1 = 1$

The statement is true for $n = 1$ .

Then, we have to check that identity is true for $n = k+1$ , under the assumption that $n = k$ is true:

$(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}$

$k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot (2\cdot k +1)^{2} = (k+1)\cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)$

$k\cdot (2\cdot k - 1)+3\cdot (2\cdot k +1) = (k + 1)\cdot (2\cdot k +3)$

$2\cdot k^{2}+5\cdot k +3 = (k+1)\cdot (2\cdot k + 3)$

$(k+1)\cdot (2\cdot k + 3) = (k+1)\cdot (2\cdot k + 3)$

Therefore, the statement is true for any $n\in \mathbb{N}$ .

4 0

3 years ago

Help please help needed

oksian1 [2.3K]

THe answer to your question is 28

6 0

3 years ago