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lawyer [7]
3 years ago
13

Jorge tiene 5 veces la edad de su hijo dentro de 15 años, tendrá únicamente el doble de la edad de su hijo ¿cuantos años tendrá

su hijo dentro de 15 años ?
Mathematics
1 answer:
miskamm [114]3 years ago
6 0

Answer:

His son will be 20 within 15 years

Step-by-step explanation:

<u><em>The question in English is</em></u>

Jorge is 5 times his son's age, within 15 years, he will only be twice his son's age. How many years will his son be within 15 years?

Let

x ----> Jorge's age now

y ----> His son's age now

we know that

x=5y -----> equation A

(x+15)=2(y+15) -----> equation B

Solve the system by substitution

Substitute equation A in equation B

(5y+15)=2(y+15)

Solve for y

(5y+15)=2y+30

5y-2y=30-15

3y=15

y=5

<em>Find the value of x</em>

x=5y ----> x=5(5)=25

so

Jorge's age now is 25 years

His son's age now is 5 years

therefore

His son will be 20 within 15 years

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This means number 1 = 180-106 = 74 degrees.

Because x and y are parallel, the top outside angle is the same as number 1.

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6x = 66

divide both sides by 6:

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7(11) -2 = 77-2 = 75 degrees.

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Andre and Elena are reading the same book over the 1 summer. Andre says he has read of the book. Elena ! says she has read 20 mo
ddd [48]

Answer: There are 175 pages in the book.

Step-by-step explanation:

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2 years ago
(a) Find a vector parallel to the line of intersection of the planes −4x+2y−z=1 and 3x−2y+2z=1.
valentinak56 [21]

Find the intersection of the two planes. Do this by solving for <em>z</em> in terms of <em>x</em> and <em>y </em>; then solve for <em>y</em> in terms of <em>x</em> ; then again for <em>z</em> but only in terms of <em>x</em>.

-4<em>x</em> + 2<em>y</em> - <em>z</em> = 1   ==>   <em>z</em> = -4<em>x</em> + 2<em>y</em> - 1

3<em>x</em> - 2<em>y</em> + 2<em>z</em> = 1   ==>   <em>z</em> = (1 - 3<em>x</em> + 2<em>y</em>)/2

==>   -4<em>x</em> + 2<em>y</em> - 1 = (1 - 3<em>x</em> + 2<em>y</em>)/2

==>   -8<em>x</em> + 4<em>y</em> - 2 = 1 - 3<em>x</em> + 2<em>y</em>

==>   -5<em>x</em> + 2<em>y</em> = 3

==>   <em>y</em> = (3 + 5<em>x</em>)/2

==>   <em>z</em> = -4<em>x</em> + 2 (3 + 5<em>x</em>)/2 - 1 = <em>x</em> + 2

So if we take <em>x</em> = <em>t</em>, the line of intersection is parameterized by

<em>r</em><em>(t)</em> = ⟨<em>t</em>, (3 + 5<em>t</em> )/2, 2 + <em>t</em>⟩

Just to not have to work with fractions, scale this by a factor of 2, so that

<em>r</em><em>(t)</em> = ⟨2<em>t</em>, 3 + 5<em>t</em>, 4 + 2<em>t</em>⟩

(a) The tangent vector to <em>r</em><em>(t)</em> is parallel to this line, so you can use

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or any scalar multiple of this.

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<em>r</em><em>(t)</em> = ⟨2<em>t</em>, 3 + 5<em>t</em>, 4 + 2<em>t</em>⟩

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frozen [14]

Answer:

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Step-by-step explanation:

The given system has equations:

x-4y=6

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Multiply the top equation by 2 to get:

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2x+2y=12

Subtract the top equation form the bottom equation to get:

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Put y=0 into x-4y=6

x-4*0=6

\implies x=6

Therefore the solution is (6,0)

4 0
3 years ago
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