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VARVARA [1.3K]
3 years ago
14

5 litres of paint cost 210 work out the cost of 50 L of paint​

Mathematics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

2100

Step-by-step explanation:

5/210=50/x

x= 50*210 / 5

x= 2100

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The triangle is an acute equilateral triangle

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\bf \sqrt[5]{x^4}\cdot \sqrt[5]{x^4}\implies \sqrt[5]{x^4\cdot x^4}\implies \sqrt[5]{x^{4+4}}\implies \sqrt[5]{x^8}\implies \sqrt[5]{x^{5+3}}
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3 years ago
Standing on a cliff 380 meters above the sea, Pat sees an approaching ship and measures its angle of depression, obtaining 9 deg
exis [7]

Answer:

(a). 2399.23 meters.

(b). 1944.19 meters apart.

Step-by-step explanation:

Please find the attachment.

We have been given that standing on a cliff 380 meters above the sea, Pat sees an approaching ship and measures its angle of depression, obtaining 9 degrees.

(a) We are asked to find how far from the shore is the ship.

We know that tangent relates opposite side of a right triangle with its adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

\text{tan}(9^{\circ})=\frac{380}{x}

x=\frac{380}{\text{tan}(9^{\circ})}

x=\frac{380}{0.158384440325}=2399.22557

Therefore, the ship is approximately 2399.23 meters away from the shore.

\text{tan}(5^{\circ})=\frac{380}{x+y}

x+y=\frac{380}{\text{tan}(5^{\circ})}

x+y=\frac{380}{0.087488663526}

2399.22557+y=4343.419875

y=4343.419875-2399.22557

y=1944.194305\approx 1944.19

Therefore, the both ships are approximately 1944.19 meters apart.

7 0
3 years ago
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