the answer is C
the dependent variable is distance, equation is y = 22x
Answer:
Step-by-step explanation:
Let's use the definition of the Laplace transform and the identity given:![\mathcal{L}[t \cos 5t]=(-1)F'(s)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bt%20%5Ccos%205t%5D%3D%28-1%29F%27%28s%29)
with ![F(s)=\mathcal{L}[\cos 5t]](https://tex.z-dn.net/?f=F%28s%29%3D%5Cmathcal%7BL%7D%5B%5Ccos%205t%5D)
.
Now, 
. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that 
.
Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that
.
Solving for F(s) on the last equation, 
, then the Laplace transform we were searching is 
I would say that the last one would be the most accurate.
Answer:
p = 8
Step-by-step explanation:
Subtract 18 from behind the equal sign to cancel it out. This leaves you with 2(p+1)- 18= 0.
Next you'll need to pull out the terms to work with the beginning of the problem. 2(p+1)- 18= 0 would turn into 2p - 16 = 2(p - 8).
This would leave you with 2= 0, but that's not true so continue on to the variable.
So p - 8= 0 making the answer p = 8
