Question

Find the equation of a line in slope-intercept form that passes through the points (-2, 20) and (3, -10).

Answer 1

Simple...

you have: (-2,20) and (3,-10,)

Using $\frac{ y_{1}- y_{2} }{ x_{1}- x_{2} }$ to find slope--->>>

$\frac{20--10}{-2-3} = \frac{30}{-5}$

=-6

m=-6

Using y=mx+b to find the equation of the line-->>>(Use any of the coordinates)

(-2,20)

20=-6(-2)+b

20=12+b

20=12+b
-12  -12

8=b

y=-6x+8

Thus, your answer.