X + 2y = 11
x - 2y = -1
---------------add
2x = 10
x = 10/2
x = 5
x + 2y = 11
5 + 2y = 11
2y = 11 - 5
2y = 6
y = 6/2
y = 3
solution is : (5,3)
Answer:
(-∞ , -6] ∪ [6 , +∞)
Step-by-step explanation:
<u>Let D be the domain of f </u>.
D = {x ∈ IR ; where x² - 36 ≥ 0}
x² - 36 ≥ 0
⇔ x² ≥ 36
⇔ x² ≥ 6²
⇔ √(x²) ≥ √(6²)
⇔ |x| ≥ 6
⇔ x ∈ (-∞ , -6] ∪ [6 , +∞)
Answer:
Step-by-step explanation:
x = 8
