The segment connecting a point on the preimage is equal to the segment connecting the point with its corresponding point on the image. Hence the relationship between the line of reflection is B. perpendicular bisector. It is not necessarily perpendicular as there are axis of symmetry that are not linear or 180 degrees
The conversion answer is 23325
The absolute value of 0.6 is 0.6 beacause its the same thing
Mean:
E[Y] = E[3X₁ + X₂]
E[Y] = 3 E[X₁] + E[X₂]
E[Y] = 3µ + µ
E[Y] = 4µ
Variance:
Var[Y] = Var[3X₁ + X₂]
Var[Y] = 3² Var[X₁] + 2 Covar[X₁, X₂] + 1² Var[X₂]
(the covariance is 0 since X₁ and X₂ are independent)
Var[Y] = 9 Var[X₁] + Var[X₂]
Var[Y] = 9σ² + σ²
Var[Y] = 10σ²
Answer:
picture from Goldbach's conjecture.
Step-by-step explanation:
Goldbach's conjecture is one of the oldest and best-known unsolved problems in number theory and all of mathematics. It states:
Every even integer greater than 2 is the sum of two primes.
The conjecture has been shown to hold for all integers less than 4 × 10^18, but remains unproven despite considerable effort.
So on the red and blue axes you see primes. The list of black numbers are even numbers.
