Change in April's weight is -7
<em><u>Solution:</u></em>
Let the initial weight be "x"
April lost 5 pounds in her first week of college
First week = lost 5 pounds
Therefore, x - 5
Over the next three weeks she lost 3 pounds, gained 2 pounds, and then lost 1 pound
<em><u>Next three week:</u></em>
Lost 3 pound
Gained 2 pound
Lost 1 pound
<em><u>Therefore, weight after 4 weeks is given as:</u></em>
x - 5 - 3 + 2 - 1 = x -7
After 4 week, the weight is x - 7
<em><u>The change in April weight is given as:</u></em>
Weight after 4 week - initial weight = x - 7 - x = -7
Thus change in April's weight is -7 (Negative sign represents loss in weight )
Answer: sec (75) or csc (15)
Step-by-step explanation:
255 is in the 3rd quadrant where the secant is. Here, the tangent and cotangent is positive.
Reference angle for 255 is,
255 - 180 = 75 degrees.
Therefore, sec (255) = sec (75)
= csc (90 - 75) = csc (15)
Answer:
y=120
Step-by-step explanation:
Y varies directly as x is written as

introducing a constant
y=kx
<em>from</em><em> </em><em>the</em><em> </em><em>ques</em><em>tion</em><em>,</em><em> </em><em>whe</em><em>n</em><em> </em><em>y</em><em>=</em><em>4</em><em>8</em><em>,</em><em> </em><em> </em><em>x</em><em>=</em><em>6</em>
<em>sub</em><em>stitute</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>form</em><em>ula</em>
<em>4</em><em>8</em><em>=</em><em>6</em><em>k</em>
<em>making</em><em> </em><em>k</em><em> </em><em>the</em><em> subject</em><em> </em><em>by </em><em>divi</em><em>ding</em><em> </em><em>thr</em><em>ough</em><em> </em><em>by</em><em> </em><em>6</em>
<em>
</em>
k=48/6
k=8
<em>put</em><em> </em><em>the</em><em> </em><em>va</em><em>lue</em><em> </em><em>of</em><em> </em><em>k</em><em> </em><em>in</em><em> </em><em>the </em><em>expression</em><em> </em><em>y</em><em>=</em><em>kx</em>
<em>y</em><em>=</em><em>8</em><em>x</em>
from the question,the value of y when x=15 is given by
y=8×15
y=120.
Answer:
1/16
Step-by-step explanation:
This means 1/2x2x2x2 = 1/16