Given,
SP~QP
SR~QR
In ∆SRP and ∆QRP
SP~QP (given)
SR~QR (given)
PR=PR (common)
Therefore,
∆SRP~∆QRP by SSS congruence rule.
Answer:
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Answer:
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Step-by-step explanation:
suplementary angles are 2 angles who's measures add to 180