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stiks02 [169]
3 years ago
13

What’s the answer to this?

Mathematics
1 answer:
Alex Ar [27]3 years ago
7 0

Answer:

the last i believe

Step-by-step explanation:

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HELP ASAP
castortr0y [4]

Answer:

y = |3x|

Step-by-step explanation:

3 0
3 years ago
A square pyramid has a base length of 4 inches. The height of each triangular face is 12 inches. What is the surface area of the
Wittaler [7]

Answer:

The surface area of the given pyramid is 112 inches^{2}.

Step-by-step explanation:

Base length of the pyramid = 4 inches

Area of the base = length^{2}

                            = 4^{2}

                            = 16

Area of its base = 16 inches^{2}

Area of one of its triangular surface = \frac{1}{2} x base x height

                                 = \frac{1}{2} x 4 x 12

                                 = 2 x 12

                                 = 24 inches^{2}

Area of all its four triangular surfaces = 4 x 24

                                                       = 96 inches^{2}

surface area of the pyramid = sum of areas of all its surfaces

                                               = 16 + 96

                                       = 112 inches^{2}

The surface area of the given pyramid is 112 inches^{2}.

8 0
3 years ago
Evaluate the iterated integral. $$ \int\limits_0^{2\pi}\int\limits_0^y\int\limits_0^x {\color{red}9} \cos(x+y+z)\,dz\,dx\,dy $$
KengaRu [80]
\displaystyle\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\int_{z=0}^{z=x}\cos(x+y+z)\,\mathrm dz\,\mathrm dx\,\mathrm dy=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(x+y+z)\bigg|_{z=0}^{z=x}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}\int_{x=0}^{x=y}\sin(2x+y)-\sin(x+y)\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left(\cos(2x+y)-2\cos(x+y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dx\,\mathrm dy
\displaystyle=\int_{y=0}^{y=2\pi}-\frac12\left((\cos3y-2\cos2y)-(\cos y-2\cos y)\right)\bigg|_{x=0}^{x=y}\,\mathrm dy
\displaystyle=-\frac12\int_{y=0}^{y=2\pi}(\cos3y-2\cos2y+\cos y)\,\mathrm dy
\displaystyle=-\frac12\left(\frac13\sin3y-\sin2y+\sin y\right)\bigg|_{y=0}^{y=2\pi}
=0
4 0
3 years ago
A squared minus 1/4 is 0. solve for a
Ludmilka [50]

Answer:

a=1/2

Step-by-step explanation:

first we need to isolate a squared. so we add 1/4 to both sides

then you take the square root of a square to get 1/2

to check, 1/2 * 1/2 = 1/4

1/4-1/4 = 0

8 0
3 years ago
Find the vertical asymptote(s) of f of x equals quantity 3 x squared plus 3x plus 6 end quantity over quantity x squared minus 2
Salsk061 [2.6K]

Answer:

a i think give me brainliest. good day.

Step-by-step explanation:

7 0
3 years ago
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