Answer:
¼ or 25% will be dihybrid organisms, ¼ will be heterozygous at first locus and recessive homozygous at other locus , ¼ of them will be recessive homozygous at first locus and heterozygous at other locus, and ¼ of them will be homozygous recessive for alleles at two independent loci.
Explanation:
A dihybrid organism is one that is heterozygous at two different genetic loci. So if we name one gene with D and other gene with R, dihybrid organism will have genotype DdRr.
If we cross that organism with the one that is homozygous recessive for alleles at two independent loci ddrr:
P: DdRr x ddrr
Answer:
Mixtures can be physically separated by using methods that use differences in physical properties to separate the components of the mixture, such as evaporation, distillation, filtration and chromatography.
Explanation:}
Answer:
Acid Sulfate Soil
Explanation:
This type of soil is represented in some soils with characteristics of high sulfate levels and high acidity.
Answer:
d) passage of a solute against its concentration gradient
Explanation:
When a solute is transported against its concentration gradient, the cells use metabolic energy. To move a substance from the region of its lower concentration to that of its higher concentration, the energy of ATP hydrolysis is utilized. These types of transport mechanisms are called active transports. If ATP hydrolysis is inhibited in a cell, it would not be able to perform the uphill movement of solutes due to the lack of any source of energy to drive the process.
Polysaccharides like Cellulose form insoluble micro-fibrils making it resistant to degradation and enzymatic activity.
<u>EXPLANATION: </u>
- Polysaccharides components in general broken down monosaccharides and they are very little enough to be absorbed by the body.
- But the polysaccharide like cellulose cannot be absorbed by our body.
- Cellulose is made up of simple polymers that form insoluble micro-fibrils results in resistant to degradation and enzymatic activity.
- Also, molecules of each micro-fibril are so tightly packed structure and prevent the penetration of enzymes.
- Thus, cellulose degradation requires a complex enzyme and cellulose.
