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2 years ago

Please help ASAP

Mathematics

1 answer:

GaryK [48]2 years ago

6 0

Answer:

Any value of k

Step-by-step explanation:

The quadratic expression can be factored into two binomials if it has two real roots.

Two real roots possible with non-negative discriminant:

D ≥ 0

As D = b² - 4ac, we get the following inequality

k² - 4(3)(-8) ≥ 0
k² + 96 ≥ 0
k² ≥ - 96

This is true for any value of k

k ∈ (- ∞, + ∞)

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Find the slope if it exits 2x-5y=6

77julia77 [94]

In standard form, slope is always the negative of the x coefficient over the y coefficient.

If you dont want to have that memorized, you can use algebra to get the equation of the line into slope-intercept form (y=mx+b)

Set it equal to y

2x - 5y = 6
2x = 5y + 6
2x - 6 = 5y
(2/5)x - 6/5 = y
Now it is in slope intercept form. In slope intercept form, the coefficient multiplying with x is the slope of the line. Therefore, the slope equals 2/5.

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3 years ago

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Suppose Mahkah makes a Native American lunch in a pot that is shaped like a right cylinder. If

Harman [31]

The pot can hold 5.23 quarts

Step-by-step explanation:

Step 1: Find the volume of the right cylinder shaped pot.

Diameter of the pot = 8 in

⇒ Radius = 4 in

Height = 6 in

⇒ Volume of the pot = πr²h = 3.14 × 4² × 6

= 301.44 in³

Step 2: Convert inches to quarts.

1 in³ = 0.017316 liquid quarts

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6 0

3 years ago

The graph shows a rectangle that has been rotated. Which statement is FALSE?

lukranit [14]

D. Is the false statement. Clearly, the rectangle was shifted and is no long in its same position

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3 years ago

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What is the equation of the quadratic graph with a focus of (1, 1) and a directrix of y = −1? PLs HELP!!

Delicious77 [7]

ANSWER
$f(x)= \frac{1}{4} {(x - 1)}^{2}$

EXPLANATION

Since the directrix is
$y = - 1$

the axis of symmetry of the parabola is parallel to the y-axis.

Again, the focus being,

$(1,1)$

also means that the parabola will open upwards.

The equation of parabola with such properties is given by,

${(x - h)}^{2} = 4p(y - k)$
where
$(h,k)$

is the vertex of the parabola.

The directrix and the axis of symmetry of the parabola will intersect at
$(1, - 1)$

The vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix.

This implies that,
$h = \frac{1 + 1}{2} = 1$

and
$k = \frac{ - 1 + 1}{2} = 0$

The equation of the parabola now becomes,

$(x - 1) ^{2} = 4p(y - 0)$

$|p| = 1$

Thus, the distance between the vertex and the directrix.

This means that,

$p = - 1 \: or \: 1$

Since the parabola opens up, we choose
$p = 1$
Our equation now becomes,

${(x - 1)}^{2} = 4(1)(y - 0)$

This simplifies to
${(x - 1)}^{2} = 4y$

or

$y = \frac{1}{4} {(x - 1)}^{2}$

This is the same as,

$f(x)= \frac{1}{4} {(x - 1)}^{2}$

The correct answer is D .

4 0

3 years ago

The x-intercept has a y coordinate of 0. True False

Ghella [55]

False, its the other way around.
The y-intercept has an x coordinate of 0.
So, false.

5 0

3 years ago