Answer:
volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a (
x + b )² dx
Step-by-step explanation:
Given the data in the question and as illustrated in the image below;
R is in the region first quadrant with vertices; 0(0,0), A(a,0) and B(0,b)
from the image;
the equation of AB will be;
y-b / b-0 = x-0 / 0-a
(y-b)(0-a) = (b-0)(x-0)
0 - ay -0 + ba = bx - 0 - 0 + 0
-ay + ba = bx
ay = -bx + ba
divide through by a
y =
x + ba/a
y =
x + b
so R is bounded by y =
x + b and y =0, 0 ≤ x ≤ a
The volume of the solid revolving R about x axis is;
dv = Area × thickness
= π( Radius)² dx
= π (
x + b )² dx
V = π ₀∫^a (
x + b )² dx
Therefore, volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a (
x + b )² dx
Answer:
log8 (2.718) = 0.48
Step-by-step explanation:
In 2.718 ÷ In 8 = 0.999896 ÷ 2.07944
= 0.4808
Answer:
x < 6
Step-by-step explanation:
1. 3x+2x = 5x
2. 5x - 8 < 22
3. 22+ 8 =30
4. 5x < 30
5. 30/5 = 6
6. x < 6
Answer:
cuteboy979409
Step-by-step explanation:
I am sorry mam a was not able to answer this question.
Answer:
24 ft
Step-by-step explanation:
a^2 + b^2 = c^2
7^2 + b^2 = 25^2
7^2 - 25^2 = -b^2
49 - 625 = -b^2
-576 = -b^2
24 = b