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2 years ago

What type of association is seen in the scatter plot.

Mathematics

1 answer:

katrin [286]2 years ago

7 0

Answer:

Girl how do you not know this is the most easiest thing /hj

Step-by-step explanation:

its a linear and strong association bc the dots are very refined and stuck together very well

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Use the Pythagorean Theorem to find the distance between points E and H. A) 3 2 B) 4 2 C) 14 D) 21

Vsevolod [243]

Answer:A

Step-by-step explanation:

because i took the usatestprep

3 0

3 years ago

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The distance between two cities on a map is 3.25 centimeters. The map used a scale in which 1 centimeter represents 20 kilometer

____ [38]

Answer:

Step-by-step explanation:

Step one:

given

we are told that the distance is 3.25cm on the map

the scale is 1cm to represent 20km

Required

the actual distance

Step two

if 1cm represent 20km

then 3.25cm will represent x km

cross multiply we have

x=2.35*20

x= 65km

Hence, the actual distance between these two cities in kilometers 65km

6 0

2 years ago

How do I solve this?

Burka [1]

you solve it by using your brain =) 132 degrees

3 0

3 years ago

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Fill in the missing expression

padilas [110]

Answer:

The complete table is:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ 0 ] = [10a + 2b + 8 ]

Explanation:

You can determine the content of each box by subtraction, running the rows and the columns.

The expressions are:

[ 5a ] + [ ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ ] + [ ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

1. First row:

[ 5a ] + [ ] + [ 4a ] = [ 10a + 3 ]

[ ] = [10a+ 3] - [ 4a ] - [ 5a ] = 10a - 4a - 5a + 3 = a + 3

2. Second colum:

[ a + 3 ] + [ 4 + a ] + [ ] = [ 3a + 8 ]

[ ] = [ 3a + 8 ] - [ a + 3 ] - [ 4 + a ] = 3a - a + a + 8 - 4 - 3 = a + 1

So far, you have completed this:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

3. Complete the row 3:

[ ] + [ a + 1 ] + [ -3a ] = [ 1 ]

[ ] = [ 1 ] - [ a + 1 ] - [ -3a ] = - a + 3a + 1 - 1 = 2a

So far, you have completed this:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

4. Complete the fourth column:

[ 10a + 3 ] + [ ] + [ 1 ] = [10a + 2b + 8 ]

[ ] = 10a + 2b + 8 - 10a - 3 - 1 = 2b + 4

So far, this is the results:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

5. Complete the second row:

[ 2b ] + [ 4 + a ] + [ ] = [ 2b + 4 ]

[ ] = [ 2b + 4 ] - [ 2b ] - [ 4 + a ] = 2b - 2b + 4 - 4 - a = - a

So far:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

6. Complete the first colum:

[ 5a ] + [ 2b ] + [2a ] = [ ]

[ ] = [ 7a + 2b ]

So far:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

7. Complete the last row:

[ 7a + 2b ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

[ ] = [10a + 2b + 8 ] - [ 7a + 2b ] - [ 3a + 8 ] = 0

The complete table is:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ 0 ] = [10a + 2b + 8 ]

5 0

3 years ago

Solve this system of equations: y = x2 – 3x + 12 y = –2x + 14 1.Isolate one variable in the system of equations, if needed. y =

gladu [14]

The values of x are 2 and -1.

Solving the equation created by substitution listed in the question:

-2x+14=x²-3x+12

Add 2x to both sides:
-2x+14+2x=x²-3x+12+2x
14=x²-1x+12

Subtract 14 from both sides:
14-14=x²-1x+12-14
0=x²-1x-2

Factoring this, we want factors of -2 that sum to -1; -2(1) = -2 and -2+1=-1:
0=(x-2)(x+1)

Using the zero product property, we know that either x-2=0 or x+1=0:
x-2=0
x-2+2=0+2
x=2

x+1=0
x+1-1=0-1
x=-1

4 0

3 years ago

Read 2 more answers