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3 years ago

10

Find the balance in the account: $1,600 principal earning 7%, compounded semi-annually, after 33 years

2 answers:

goldfiish [28.3K]3 years ago

8 0

A principal invested for n number of years increases as the equation projects F = P * (1+ i) ^n where F is the future worth, p is the present worth or principal and i is the interest rate. substituting, F = $1600 * (1+ 0.07/2) ^33*2 equal to amount of future worth or balance of $15494.70

ASHA 777 [7]3 years ago

5 0

Answer:

$15,494.70

Step-by-step explanation:

Compounding twice year, 3.5% each, 66 times

result=$1,600*1.035^66 = $15,494.70

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Simplify to create an equivalent expression. 8−4(−x+5)

White raven [17]

8 - 4(-x + 5)

As you already know, in order to find the equivalent expression to our already given one, we have to simplify it first :)

8 +4x - 20

**Remember that a negative times a negative is always a positive!!**

Add like terms.

4x + (8 - 20)

Simplify.

4x + (-12)

Get rid of parenthesis.

4x - 12

Look at our answer choices.

Our answer is a. 4x - 12

~Hope I helped!~

3 0

3 years ago

Can you help me????????

aev [14]

Check the picture below.

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8 0

4 years ago

option 1 drop down are: even-odd identity, quotient identity, Pythagorean identity, double-number identity.option 2 drop down ar

motikmotik

Answer:

The equation is given below as

$\frac{\cos2x}{\cos x}=\cos x-\sin x\tan x$

Step 1:

We will work on the left-hand side, we will have

$\begin{gathered} \cos x-\sin x\tan x \\ \text{recall that,} \\ Quoitent\text{ identity is} \\ \tan x=\frac{\sin x}{\cos x} \end{gathered}$

By substituting the identity above, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x}=\cos x-\frac{\sin^2x}{\cos x} \\ \end{gathered}$

Here, we will make use of the quotient identity

Step 2:

By writings an expression, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x} \\ \cos x-\sin x\tan x=\frac{\cos^2x-\sin^2x}{\cos x} \end{gathered}$

Here, we will use the definition of subtraction

$\cos x-\frac{\sin^2x}{\cos x}$

Step 3:

We will apply the double number identity given below

$\begin{gathered} \cos 2\theta=\cos (\theta+\theta)=\cos ^2\theta-\sin ^2\theta \\ \cos 2x=cos(x+x)=\cos ^2x-\sin ^2x \end{gathered}$

By applying this, we will have

$\frac{\cos^2x-\sin^2x}{\cos x}=\frac{\cos2x}{\cos x}$

Here, we will use the double number identity

$\frac{\cos^2x-\sin^2x}{\cos x}$

5 0

1 year ago

What numbers are mulitply and equals negative 30 and when add equals to negative 25

timofeeve [1]

This is impossible without getting a never ending decimal somewhere between 1.14 and 1.15.

3 0

4 years ago

Do number 5 pleaseee

swat32

Answer:

A

Step-by-step explanation:

16 × 2 = 32

20 × 2 = 40

hshsjbdjidjeje

6 0

3 years ago