All categories

2 years ago

What is the measure of the angle x?

Mathematics

1 answer:

NISA [10]2 years ago

5 0

Answer:

Step-by-step explanation:

angle AOB= 2x=80

x=80/2

x=40

You might be interested in

On the number line, which point is closest to <br> A. A<br> B. B <br> C. C <br> D. D

oksano4ka [1.4K]

Point C, since pi=around 3.14

Hope that helps :)

4 0

3 years ago

Read 2 more answers

Lamar goes shopping for a new flat-panel television. A television is usually described by the length of the screen's diagonal. H

sp2606 [1]

Answer:

The width is 36.4 inches

Step-by-step explanation:

we know that

Applying teh Pythagorean Theorem

$D^2=h^2+W^2$

where

D is the length of the diagonal of the television

W is the width

h is the height

substitute the given values

$42^2=21^2+W^2$

solve for W

$W^2=42^2-21^2\\W^2=1,323\\W=36.4\ in$

6 0

3 years ago

Which one is a prime number?,11,21,51,

Lana71 [14]

11 is only divisible by 1 and 11, it is a prime number. 21 is visible by 1, 3, 7, and 21; not a prime number. 51 is divisble by 1, 3, 7, 17, and 51; not a prime number. 11 is the only prime number .

5 0

3 years ago

Read 2 more answers

The probabilities that a batch of 4 computers will contain 0, 1, 2, 3, and 4 defective computers are 0.4096, 0.4096, 0.1536, 0.0

Zinaida [17]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And if we replace we got:

$E(X) = 0*0.4096 +1*0.4096+ 2*0.1536+ 3*0.0256 +4*0.0016 = 0.8$

So we expect about 0.8 defective computes in a batch of 4 selected.

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

Solution to the problem

For this case we have the following distribution given:

X 0 1 2 3 4

P(X) 0.4096 0.4096 0.1536 0.0256 0.0016

And we satisfy that $P(X_i) \geq 0$ and $\sum P(X_i) =1$ so we have a probability distribution. And we can find the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And if we replace we got:

$E(X) = 0*0.4096 +1*0.4096+ 2*0.1536+ 3*0.0256 +4*0.0016 = 0.8$

So we expect about 0.8 defective computes in a batch of 4 selected.

5 0

4 years ago

If a1 = 7 and an = -2an-1 then find the value of a5

alukav5142 [94]

Answer:

$a_1 = 7 \\ a_n = - 2a_{n - 1} \\ a_2 = - 2a_1 = - 2(7) = - 14 \\ a_3 = - 2a_2 = - 2( - 14) = 28 \\ a_4 = - 2a_3 = - 2(28) = - 56 \\ a_5 = - 2a_4 = - 2( - 56) = 112$

7 0

2 years ago