<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
Answer:
the triangle or the box inside the box i see y u need help lolz
Step-by-step explanation:
I see two ways to do it.
First, you have to understand that when you see a 'complex fraction' like this, the top number is a numerator, and the two bottom numbers are both denominators.
Way-1:
Take the top fraction . . . 2/2 . That's equal to 1 . So the whole thing is <em>1/3</em>.
Way-2:
Multiply the bottom two denominators. Then the whole thing is 2/(2·3) . That's the same thing as 2/6 . Simplify that, and you have <em>1/3</em> .
Answer:
A bi conditional statement is a combination of a conditional statement and its converse written in the if and only if form. Two line segments are congruent if and only if they are of equal length
Step-by-step explanation:
Answer:
the 1 one will be the answer