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jeka57 [31]
2 years ago
6

Given that 5 miles is 8 km, convert 17.8 miles to km.

Mathematics
1 answer:
Sav [38]2 years ago
7 0

Answer:

28km

Step-by-step explanation:

5miles = 8km

17.8miles = x

\frac{17.8}{5}  \times 8km

x = 28km

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A glass is
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Answer:

Step-by-step explanation:

4/7 x + 70 cm^3 = 3/4 x          Subtract 4/7 x from both sides

3/4 x - 4/7 x = 70 cm^3          The lowest common denominator is 28

\frac{3*7*x}{4*7} - \frac{4*4x}{4*7} = 70 cc\\\frac{21*x}{28} - \frac{16*x}{28} = 70 cc\\\frac{5x}{28}= 70cc\\

5x = 70*28

5x = 1960                                Divide by 5

x = 1960/5

x = 392 cc

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3 years ago
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16 over 3 is the answer u write the numerator above the denominator 6 over 1 minus 2 over 3 6 times 3 over 1 x3 minus 2 over 3 u get 18 minus 2 over 3 and subtract 18 and 2 u get 16 over 3

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2 years ago
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Write <, >, or = to make the statement true : .293 ___ .29
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7 0
3 years ago
Listed below are the overhead widths​ (in cm) of seals measured from photographs and the weights​ (in kg) of the seals. Construc
Anarel [89]

Answer and Step-by-step explanation: Scaterplot is a type of graphic which shows the relationship between to variables. In this question, you want to determine if there is a linear relationship between overhead widths of seals and the weights. So, the hypothesis are:

H₀: no linear correlation;

H₁: there is linear correlation;

In this hypothesis test, to reject H₀, the correlation coefficient r of the data set has to be bigger than the critical value from the table.

With α = 0.05 and n = 6, the critical value is 0.811.

The linear correlation is calculated as:

r = n∑xy - ∑x.∑y / √[n∑x² - (∑x)²] [n∑y² - (∑y)²]

r = \frac{6.9632 - 51.1108}{\sqrt{6.439 - (51^{2} )}.6.14482 - (1108^{2} ) }

r = 0.9485

Since r is bigger than the critical value, H₀ is rejected, which means there is enough evidence to conclude that there is linear correlation between overhead widths and the weights.

In the attachments is the scaterplot of the measurements, also showing the relationship.

5 0
3 years ago
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