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soldier1979 [14.2K]
3 years ago
14

Complete the following statement about the given rectangular and triangular pyramids:

Mathematics
1 answer:
Reptile [31]3 years ago
7 0

Answer:

getting pointhdnndndmdkdkdnsnkss

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The subject of the formula below is y.<br>a=4x/t - p<br>Rearrange the f make x the subject.​
Crazy boy [7]

Answer:

x = t(a+p)/4

Step-by-step explanation

Given the expression

​a=4x/t - p

We are to make x the subject of the formula

a=4x/t - p

Add p to both sides

a+p = 4x/t - p+p

a+p = 4x/t

Cross multiply

t(a+p) = 4x

Rearrange

4x = t(a+p)

Divide both sides by 4

4x/4 = t(a+p)/4

x = t(a+p)/4

4 0
3 years ago
What is the solution to 89+k=-42
fiasKO [112]
Subtract 89 from -42. k=-131
6 0
3 years ago
Read 2 more answers
A ship traveled 120 km with the current, and then turned around and traveled back, spending 5h and 24 min on its trip. Find the
nadya68 [22]

Yah same im also an RSM student. 8th Honors?

7 0
3 years ago
2^2/5+ 3^1/10 <br> HELP ASAP
gizmo_the_mogwai [7]

Answer:

\sqrt[5]{4}  + \sqrt[10]{3}

Step-by-step explanation:

We sure can write 2^2/5+ 3^1/10 as 2^{\frac{2}{5} } + 3^{\frac{1}{10} }

// use the a^{\frac{m}{n} }  =\sqrt[n]{a^{m} } to transform the expression

Convert 2^{\frac{2}{5} } to \sqrt[5]{2^{2} } = \sqrt[5]{4}                        (here a = 2, n = 5, m = 2)

Then convert  3^{\frac{1}{10} } to \sqrt[10]{3^{1} } = \sqrt[10]{3}             (here a = 3, n = 10, m = 1)

Now we get  2^{\frac{2}{5} } + 3^{\frac{1}{10} } = \sqrt[5]{4}  + \sqrt[10]{3} . This is the simplified form, which is the answer.

6 0
3 years ago
Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, the
NeX [460]

Answer:

m = -1/6.

b = 5.

Step-by-step explanation:

Slope m =  (3 - 6) / (12 - -6)

=  -3 / 18

= -1/6.

y = -1/6 x + b

when x = 12 y = 3 so

3 = -1/6 * 12 + b

b =  3 + 2 = 5.

5 0
3 years ago
Read 2 more answers
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