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Yuliya22 [10]
2 years ago
6

How do we find the time complexity for this algorithm?

Computers and Technology
1 answer:
gizmo_the_mogwai [7]2 years ago
8 0

Answer:

For any loop, we find out the runtime of the block inside them and multiply it by the number of times the program will repeat the loop. All loops that grow proportionally to the input size have a linear time complexity O(n) . If you loop through only half of the array, that's still O(n) .

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The first computer program was used to help the analytical engine calculate numbers. Who invented that program?
nikdorinn [45]

Answer:

Charles Babbage

Explanation:

Analytical engines were presumed to be the first general-purpose computer which was designed sometime in the 19th century by Charles Babbage -  a British mathematician and inventor. A series of punch cards was used by Charles Babbage in his design of the engine. These punch cards were used for various operations such as arithmetical operations, numerical constants and other operations such as load and store.

<em>Hope this works!</em>

8 0
3 years ago
Each time the enter key is pressed, word creates a new paragraph. (points : 2) true false
ludmilkaskok [199]
Your answer would be true
6 0
3 years ago
The Securities and Exchange Commission (SEC) was created to develop and approve a set of common international accounting rules.
Dennis_Churaev [7]

Answer:  

Idk search it on google chrome

Explanation:

3 0
3 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
The current in a resistor is 5.0 A, and its power is 60 W. What is the voltage?
alexandr1967 [171]

The voltage on a resistor will be "12 V".

According to the given question,

Current,

  • I = 5.0 A

Power,

  • P = 60

As we know the formula,

→ Power (P)= Current(I)\times Voltage (V)

or,

→              V = \frac{P}{I}

By putting the giving values, we get

→                  = \frac{60}{5}

→                  = 12 \ V

Thus the solution above is right.

Learn more about voltage here:

brainly.com/question/18883096

8 0
3 years ago
Read 2 more answers
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