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2 years ago

Find the number that makes the ratio equivalent to 1:9. 7:

Mathematics

1 answer:

alex41 [277]2 years ago

6 0

Answer:

7:63

Step-by-step explanation:

It's a 1 to 9 ratio, which means the second number is 9 times bigger.

To make it equivalent, you need to make 7 9 times bigger as well.

7x9=63

Answer: 7:63

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What does the model predict for 1900?

vagabundo [1.1K]

Answer:

64.0% is the correct answer.

Step-by-step explanation:

As per the given scatter plot of voter turnout every year:

X axis represents the year and

Y axis represents the percentage of people who voted.

The model was predicted as per the equation:

$y = -0.1271x + 307.53$

<u>To find:</u> Prediction for the year 1900.

Putting the value of $x=1900$ , the value of y will be the predicted value of the model i.e. the value of percentage of voter turnout.

$\Rightarrow y = -0.1271\times (1900) + 307.53\\\Rightarrow y = -241.49 + 307.53\\\Rightarrow y = -64.04\%\\OR\\y \approx 64.0\%$

So, the model predicts $y \approx 64.0\%$ for the year 1900.

3 0

3 years ago

What is more precise 4.33g;4337mg

Vesna [10]

4337 mg is much more precise as compared to 4.33 grams (which is obviously rounded).

Hope this helps :)

6 0

4 years ago

Mai thinks of a secret number. She says that her secret number is more than 11 units away from 50. Write an absolute- value ineq

Vitek1552 [10]

Given:

Secret number is more than 11 units away from 50.

To find:

The absolute- value inequality that gives the possible values of Mai's number.

Solution:

Let the secret number be x.

Secret number is more than 11 units away from 50. It may be less than 50 or more than 50.

Case 1: If x<50, then $50-x>11$

Case 2: If x>50, then $x-50>11$

It means the absolute difference between secret number and 50 is greater than 11.

$|x-50|>11$

Therefore, the required inequality is $|x-50|>11$ .

5 0

3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$