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Alina [70]
3 years ago
13

Which of the following is the number of sides a polygon can have to form a regular tessellation?

Mathematics
2 answers:
Ber [7]3 years ago
7 0

Answer with explanation:

Three Different, Regular tessellation is formed,1. if we join regular polygons of side 3,called equilateral triangle,2. Regular polygon of side 4,called Square,and 3. Regular polygon of side ,6 called hexagon,

to form a pattern.

→A polygon is said to be regular ,if it's all interior angle and all sides are equal.

Regular polygon of side 3, when joined together can be named as: "3.3.3".

Regular polygon of side 4, when joined together can be named as: "4.4.4".

Regular polygon of side 6, when joined together can be named as: "6.6.6".

So, a regular tessellation is formed , from regular polygon having,3,4 and 6 Sides.

→None of the sides of the polygon, which is given in the option ,can be used to form a regular tessellation.

None of the option is true.

Alex Ar [27]3 years ago
4 0
D.5 the answer is D.5
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\bf \textit{internal division of a line segment using ratios} \\\\\\ A(-9,-7)\qquad C(x,y)\qquad \qquad \stackrel{\textit{ratio from A to C}}{1:2} \\\\\\ \cfrac{A\underline{B}}{\underline{B} C} = \cfrac{1}{2}\implies \cfrac{A}{C}=\cfrac{1}{2}\implies 2A=1C\implies 2(-9,-7)=1(x,y)\\\\[-0.35em] ~\dotfill\\\\ B=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill

\bf B=\left(\cfrac{(2\cdot -9)+(1\cdot x)}{1+2}\quad ,\quad \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}\right)~~=~~(-4,-6) \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -9)+(1\cdot x)}{1+2}=-4\implies \cfrac{-18+x}{3}=-4 \\\\\\ -18+x=-12\implies \boxed{x=6} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}=-6\implies \cfrac{-14+y}{3}=-6 \\\\\\ -14+y=-18\implies \boxed{y=-4}

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3 years ago
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