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asambeis [7]
2 years ago
13

Which rule dilates a figure in the coordinate plane by a scale factor of 5?

Mathematics
2 answers:
FromTheMoon [43]2 years ago
4 0

Dilation involves changing the size of a figure

The dilation rule of a figure in the coordinate plane by a scale factor of 5 is (b) (x,y) \to (5x,5y)

<h3>How to determine the dilation rule?</h3>

The scale factor (k) is given as:

k = 5

Assume the coordinates of the figure is (x,y)

The dilation rule would be:

(x,y) \to k(x,y)

Substitute 5 for k

(x,y) \to 5(x,y)

Expand

(x,y) \to (5x,5y)

Hence, the dilation rule is (b) (x,y) \to (5x,5y)

Read more about dilation at:

brainly.com/question/3457976

Anvisha [2.4K]2 years ago
4 0

If the coordinate plane is dilated by a scale factor of 5, hence the resulting coordinate of the preimage will be (5x, 5y)

<h3>Dilation of coordinate</h3>

Dilation is a transformation technique that changes the size and shape of an object in an xy plane

If the coordinate point (x, y) is dilated by a factor of "k", the resulting coordinate of the preimage will be (kx, ky)

If the coordinate plane is dilated by a scale factor of 5, hence the resulting coordinate of the preimage will be (5x, 5y)

Learn more on dilation here: brainly.com/question/10253650

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uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
4 years ago
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