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Natasha2012 [34]
2 years ago
12

HELP PLEASE PYTHAGOREOM THEOREM

Mathematics
1 answer:
sp2606 [1]2 years ago
7 0

Pythagorean Theorem:

a^2 + b^2 = c^2

Since 10 and 24 are the legs, "x" has to be the hypoteneuse.  "a" and "b" are the legs (10 and 24).

Now, replace the values in.

10^2+24^2 = x^2

x^2 = 100+576\\x^2 = 676\\x = 26

Hope this helped! :)

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Every hour 52 people throw a nickel into the fountain. How many hours will it take before there is more than $350 in the fountai
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Divide 52 by 350 which equals 0.1485
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4 years ago
Suppose that A A is a set containing 13 13 elements. Find the number of different subsets of A.
aivan3 [116]

Answer:

number of subsets of a set with 13 elements are: 2^{13}

Step-by-step explanation:

In order to solve this intuitively, we can start by a set with lesser elements. This will reveal a pattern that will be used to solve for the subsets of the 13 element set.

If we start with a set B. which contains only 3 elements.

B = \{1,2,3\}

how many subsets of B are there? well we can count them. [the set containing {1,2} and {2,1} are the same, arrangement doesn't matter]

B_{0} = \{\}\\B_{1a}=\{1\}\\B_{1b}=\{2\}\\B_{1c}=\{3\}\\B_{2a}=\{1,2\}\\B_{2b}=\{2,3\}\\B_{2c}=\{3,1\}\\B_{3a}=\{1,2,3\}\\

there are a total of 9 subsets here.

Similarly, if you try a with a subset with only two elements you'll find that it has a total of 4 subsets.

We can see that combinatorics is at play here.

for the set B. the number of subsets can be written as:

\text{\# of subsets of B} = ^3C_0+^3C_1+^3C_2+^3C_3\\\text{\# of subsets of B} = 1+3+3+1\\\\text{\# of subsets of B} = 8

if we try with a 2-element set:

\text{\# of subsets} = ^2C_0+^2C_1+^2C_2\\\text{\# of subsets} = 1+2+1\\\ \text{\# of subsets} = 4

We can use the same technique to find the number of subsets of the 13 element set.

But if you recognize a pattern here that this sets of combinations are actually part of the pascal triangle, the sum of each row of the triangle is 2^{the row's number}. hence.

\text{\# of subsets of B} = 2^3\\\ \text{\# of subsets of B} = 8

So finally, the subsets of a 13-element set A will be

\text{\# of subsets of A} = ^{13}C_0+^{13}C_1+^{13}C_2+^{13}C_3\cdots+^{13}C_{12}+^{13}C_{13}\\OR\\\text{\# of subsets of A} = 2^{13}\\\text{\# of subsets of A} = 8192

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Answer:

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Step-by-step explanation:

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Answer:

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