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3 years ago

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A researcher posts an online advertisement offering $25 in exchange for participation in a short study. The researchers accepts

the first 10 people who respond to the advertisement. Which of the following is true about the sample.

1 answer:

Anarel [89]3 years ago

5 0

In this case, I say the answer is A because most short studies dont create valid samples. It all depends on what the short study was about...

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Smallville High School scored more than 30 points in their last football game entirely from safeties and field goals. (In

Reika [66]

Inequalities help us to compare two unequal expressions. The inequality for this scenario in standard form is 2x + 3y > 30.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

Let the safety counts be represented by x, while the field goal count is represented by y.

Part A: The inequality for this scenario in standard form.

2x + 3y > 30

Part B: The inequality in slope-intercept form.

2x + 3y > 30

3y > 30 - 2x

y > 10 - (2/3)x

y < (2/3)x - 10

PartC: The inequality is represented below.

Learn more about Inequality:

brainly.com/question/19491153

#SPJ1

7 0

1 year ago

Julio caught 3 fish weighing a total of 23 1/2 pounds. One fish weighed 9 5/8 pounds and another weighed 6 1/4 pounds. How much

Airida [17]

So we need to know what 23 1/2 + 9 5/8 + 6 1/4 is.
first, we need to make them into equivalent fraction.
so...
23 1/2 can be 23 4/8
9 5/8 and
6 1/4 can be 6 2/8
let's add the whole numbers.
23 + 9 + 6 = 38
4/8 + 5/8 + 2/8 = 11/8 = 1 3/8
so 38 + 1 3/8 is 39 3/8
the answer is 39 3/8 pounds

4 0

3 years ago

Read 2 more answers

Solve the initial-value problem<br><br> y' = x^4 - \frac{1}{x}y, y(1) = 1.

natta225 [31]

The ODE is linear:

$y'=x^4-\dfrac yx$

$y'+\dfrac yx=x^4$

Multiplying both sides by $x$ gives

$xy'+y=x^5$

Notice that the left side can be condensed as the derivative of a product:

$(xy)'=x^5$

Integrating both sides with respect to $x$ yields

$xy=\dfrac{x^6}6+C$

$\implies y(x)=\dfrac{x^5}6+\dfrac Cx$

Since $y(1)=1$ ,

$1=\dfrac16+C\implies C=\dfrac56$

so that

$\boxed{y(x)=\dfrac{x^5}6+\dfrac5{6x}}$

4 0

3 years ago

Answer this question please and thank you

olga nikolaevna [1]

4 for the second one and 2 for the second

3 0

3 years ago

Read 2 more answers

Please solve this question.

Fantom [35]

Answer:

2 by 2

Step-by-step explanation:

$A = \begin{pmatrix} 1 & 2\\3 & 4\end{pmatrix}$

Since, given matrix has 2 rows and 2 columns.

So, Its a 2 by 2 order matrix.

6 0

2 years ago

Read 2 more answers