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stellarik [79]
3 years ago
15

A researcher posts an online advertisement offering $25 in exchange for participation in a short study. The researchers accepts

the first 10 people who respond to the advertisement. Which of the following is true about the sample.
Mathematics
1 answer:
Anarel [89]3 years ago
5 0
In this case, I say the answer is A because most short studies dont create valid samples. It all depends on what the short study was about...
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A candidate took a phone poll of 110 people. Of the 110 people polled, 87 said they would vote for the other person. There are 9
SSSSS [86.1K]

Option B

7569 number of people are going to vote for the other candidate

<em><u>Solution:</u></em>

Given that candidate took a phone poll of 110 people

Of the 110 people polled, 87 said they would vote for the other person

There are 9570 people in the district

You can set up this problem like a proportion

Let "x" be the number of people who would vote for the other candidate

\frac{87}{110} = \frac{x}{9570}

To solve proportions, you cross-multiply. This means you multiply the numerator by the other denominator, and the denominator by the other numerator

87 \times 9570 = 110 \times x

832590 = 110x

x = 7569

Thus 7569 number of people are going to vote for the other candidate

6 0
3 years ago
Read 2 more answers
Determine the median of the numbers: 6 5 2 2 5 00
zavuch27 [327]

Answer:

2

Step-by-step explanation:

6 0
3 years ago
Helpmeeee please!!!!!
Akimi4 [234]

Answer:

Step-by-step explanation:

5 0
3 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
U Listen
Elena L [17]

Answer:

6

Step-by-step explanation:

60 mins ÷5= 12. 12 x2=24

60 mins ÷6=10. 10x3=30

30-24=6

4 0
3 years ago
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