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2 years ago

6

Bella baked a two layer cake.The bottom layer has dimensions of 4 inch x 6inch x 8inch.The dimensions of the top layer are half

bottom.What is the volume of the top layer.

1 answer:

Flura [38]2 years ago

3 0

Answer:

30 is the answer because you need to multiple 4 and 6

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Kevin plans to put concrete on a rectangular portion of his driveway. The portion is 10 feet long and 3 inches high. The price o

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3 feet wide hope it helps

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3 years ago

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At a construction job for a house there are 40 painters.of these painters 85% of them paint the interior of the house.how many p

grandymaker [24]

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34 painters were painting the interior

Step-by-step explanation:

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3 years ago

Which hill described in the table is the steepest and why?

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Step-by-step explanation:

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3 years ago

First derivative of <br>√{cosec2x).show with full step.

Mice21 [21]

Answer:

$- \sf \displaystyle \: \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }$

Step-by-step explanation:

we are given a derivative

$\displaystyle \: \frac{d}{dx} ( \sqrt{ \csc(2x) } )$

and said to figure out the first derivative

to do so

recall chain rule:

$\sf\displaystyle \: \frac{d}{dx} (f(g(x)) = \frac{d}{dg} (f(g(x)) \times \frac{d}{dx} (g)$

so we get

$\displaystyle \: g(x) = \csc(2x)$

rewrite the derivative using the chain rule:

$\displaystyle \: \frac{d}{dg} ( \sqrt{ g } ) \times \frac{d}{dx} ( \csc(2x) )$

use square root derivative rule to simplify:

$\displaystyle \: \frac{1}{ 2\sqrt{g} } \times \frac{d}{dx} ( \csc(2x) )$

now we need to again use chain rule composite function derivative to simplify

where we'll take a new function n so we won't mess up two g's and we'll take 2x as n

use composite function derivative to simplify:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times \frac{d}{dn}( \csc(n) ) \times \frac{d}{dx} (2x)$

use derivative formula to simplify derivatives:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times - \cot(n) \csc(n) \times 2$

substitute the value of n:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{g} } \times - 2\cot(2x) \csc(2x)$

substitute the value of g:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{ \csc(2x) } } \times - 2\cot(2x) \csc(2x)$

now we need our trigonometric skills to simplify

rewrite cot and csc:

$\sf \displaystyle \: \frac{1}{ 2\sqrt{ \csc(2x) } } \times - 2 \dfrac{ \cos(2x) }{ \sin(2x) } \dfrac{1}{ \sin(2x) }$

simplify multiplication:

$\sf \displaystyle \: \frac{1}{ \cancel{ \: 2}\sqrt{ \csc(2x) } } \times \cancel{- 2} \dfrac{ \cos(2x) }{ \sin ^{2} (2x) }$

simplify multiplication:

$- \sf \displaystyle \: \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }$

4 0

3 years ago

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skelet666 [1.2K]

Answer:

The answer is 10$ per shirt

Step-by-step explanation:

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4 years ago

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