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attashe74 [19]
3 years ago
6

Please help me also if you know how to delete other peoples post that would be great

Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

he earned $15.2

Step-by-step explanation:

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Please show me how you find x and determine what x is <br> Thank you I appreciate it :)
AfilCa [17]

well, let's notice something, we have two 45° angles, now each of those will give use an equal opposite side, namely if that one side is "x", the other is her twin, "x" as well.

is a right-triangle, so we can use the pythagorean theorem, and we know the sides are x,x,6.


\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies 6^2=x^2+x^2 \qquad \begin{cases} c=\stackrel{hypotenuse}{6}\\ a=\stackrel{adjacent}{x}\\ b=\stackrel{opposite}{x}\\ \end{cases} \\\\\\ 36=2x^2\implies \cfrac{36}{2}=x^2\implies 18=x^2\implies \sqrt{18}=x\implies \sqrt{9\cdot 2}=x \\\\\\ \sqrt{3^2\cdot 2}=x\implies \boxed{3\sqrt{2}=x}

7 0
3 years ago
I HAVE 15 minutes HELP
Tju [1.3M]

Answer:

1817

Step-by-step explanation:

4 0
3 years ago
"the advrage a of 2 numbers c and d is equal to half the sum of c and d " this whole qustion confuses the I am basically suppose
olga_2 [115]

Answer:

\frac{c + d}{2}

Step-by-step explanation:

this is the equation used to find the average of two numbers.

8 0
3 years ago
Type the correct answer in the box. Spell all words correctly.
Crank

The comlete question with the diagram is in the picture attached.

Answer:

Point   \boxed{\text{   E    }}   is the vertex of the angle marked in the figure.

Explanation:

When two lines intersect each other they will form an <em>angle</em> and the intersection point will be the <em>vertex of the angle</em>.

In the figure attached, the line that joins the points A and B and the line that joins the points C and D intersect at the point E, forming the corresponding angle (shadowed in the figure).

Such intersection point, which marks the angle, is the vertex of the angle.

3 0
3 years ago
Helpppp pleaseeee!!!
Mashcka [7]

= 20 \frac{ {..144y. \frac{ \leqslant y.}{?} }^{?} }{?} 5 \time41s \frac2{9} < .40.2{0}  {. \times \frac{?}{?} }^{?}

6 0
2 years ago
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